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Dimas [21]
2 years ago
10

Mass=35g, density=5g/cm3. what is the volume?

Chemistry
1 answer:
nevsk [136]2 years ago
8 0

Answer:

7 cm^3

Explanation:

Density = Mass/Volume

5 = 35/x

multiply both sides by x to get

5x = 35

then divide by 5

so x = 7 cm^3

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Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
2 years ago
A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
Anestetic [448]

Answer:

mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

m = 10 - 2m

3m = 10

m = 10/3

m = 3.33 g of X

Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

8 0
3 years ago
Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8
zubka84 [21]

<u>Answer:</u> The half life of the reaction is 1190.7 seconds

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

k = rate constant of the reaction = 5.82\times 10^{-4}s^{-1}

t_{1/2} = half life of the reaction = ?

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{5.82\times 10^{-4}s^{-1}}=1190.7s

Hence, the half life of the reaction is 1190.7 seconds

8 0
3 years ago
Help i give more point this time​
dmitriy555 [2]

Answer:

It's a type of chemical bond that emerges because of electrostatic force between electrons and positive metal charges.

Explanation:

I don't know if this is what you are looking for but i don't mind if you copy it.

3 0
2 years ago
Calcium reacts with oxygen to form calcium oxide. Name the<br> reactants.
LUCKY_DIMON [66]
CaO
Calcium reacts with oxygen to form calcium oxide. The chemical equation for this reaction is Ca + O2 → CaO.
7 0
2 years ago
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