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Dimas [21]
2 years ago
10

Mass=35g, density=5g/cm3. what is the volume?

Chemistry
1 answer:
nevsk [136]2 years ago
8 0

Answer:

7 cm^3

Explanation:

Density = Mass/Volume

5 = 35/x

multiply both sides by x to get

5x = 35

then divide by 5

so x = 7 cm^3

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To change an object from a liquid to a gas _________ must happen
nignag [31]
Evaporation!
-Melting is a solid to a liquid
-sublimation is directly from a solid to a gas
-condensation gas to liquid
4 0
3 years ago
Identify each process numbered 1-6
Vedmedyk [2.9K]

Answer:

1 = Melting

2 = Freezing

3 = Sublimation

4 = Deposition

5 = Condensation

6 = Boiling

Explanation:

7 0
3 years ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
How many moles of water are produced from 19.2 g of B2H6
lbvjy [14]
The Balanced chemical equation of reaction of Borane with oxygen is as follow,
                                  B₂H₆ + 3O₂ -----> 2HBO₂ + 2H₂O
According to this equation 27.66 g (1 mole) of B₂H₆ reacts with oxygen to produce 36 g (2 moles) of water.
The amount of water produced when 19.2 g of B₂H₆ reacted is calculated as follow,
\frac{27.66 g B2H6 produced}{19.2 g of B2H6 will produce} = \frac{36 g of H2O}{x g of water}
Solving for x,                       
              x = (36 g of H₂O ₓ 19.2 g of H₂B₆) / 27.66 g of B₂H₆

              x = 24.98 g of H₂O

Result:
           24.98 g 
of water is produced when 19.2 g of B₂H₆ is reacted with excess of oxygen.
5 0
3 years ago
If a 22.4 L volume of a sample of gas has a density of 0.900 grams/L at 1.00 atm and 0.00°C. Given
disa [49]

Answer:

Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)

Explanation:

Use Ideal Gas Law formula to determine formula weight and compare to formula weights of answer choices.

PV = nRT = (mass/fwt)RT => fwt = (mass/Volume)RT = Density x R x T

Density = 0.900 grams/L

R = 0.08206 L·atm/mole·K

T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)

= 20.1 g/mol => Neon (Ne)

4 0
3 years ago
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