Mass=35g, density=5g/cm3. what is the volume?

What is the density of fluorine gas, F2, at STP? E) 0.848 g/L B) 1.18 g/ L C ) 1.70 g/L D) 0.589 g/L

Gre4nikov [31]

Answer:

C ) 1.70 g/L

Explanation:

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRt

At STP,

Pressure = 1 atm

Temperature = 273.15 K

Molar mass of fluorine gas = 38 g/mol

Applying the equation as:

1 atm × 38 g/mol = d × 0.0821 L.atm/K.mol × 273.15 K

3 0

3 years ago

Which of the compounds h2c2o4, ca(oh2, koh, and hi, behave as bases when they are dissolved in water?

Galina-37 [17]

H2C2O4, also written as (COOH)2, is Ethandioic acid, and, as evident by the name, is an acid, and not a base
Ca(OH)2 and KOH, Calcium Hydroxide and Potassium Hydroxide, respectively, are bases when dissolved in water, as they are able to release OH- ions.
Hydrogen Iodide, HI, when dissolved in water, is a strong acid. So, that is also not a base.

6 0

3 years ago

Read 2 more answers

Hydrogen cyanide is poisonous liquid that has a faint, almond-like smell. One molecule of hydrogen cyanide (HCN) is made up of o

sergeinik [125]

"<span>H-C=N:" is the one answer among the choices given in the question that shows the correct dot diagram. The correct option among all the options that are given in the question is the fourth option or option "D". The other choices can be neglected. I hope that this is the answer that has come to your help.</span>

5 0

3 years ago

Read 2 more answers

If 3 g of element C combine with 8 g of element D to

Scrat [10]

16 grams because you multiply 8x2

5 0

3 years ago

100 POINTS! PLEASE HELP! QUESTIONS ARE IN THE PICTURES. WILL GIVE BRAINLIEST, 5-STAR RATING, and THANKS. HALF-DONE ANSWERS WILL

Elenna [48]

Answer:

See Explanations....

Explanation:

NOTE => See attached graph.

1. 25-Turn Electromagnet

a. Strength of Batteries 1.5v vs 6.0v

6v:1.5v => 4:1 voltage ratio => That is, 6v battery is 4x voltage of 1.5v battery.

b. Ratio of Paperclips Picked Up

23clips(6v):6clips(1.5v) => 3.8clips(6v):1clip(1.5v)

That is, the 6 volt battery-EM picks up 3.8x more clips than the 1.5v battery-EM assuming constant number of coils given.

c. Empirical Relationship

From data given, an increase in voltage (V) produces a proportional increase in number of paperclips (C) picked up. Such is a Direct Relationahip between #Clips Picked Up and Battery Voltage.

Thus, C ∝ V => C = kV => k = C/V

Therefore, for k₁ = k₂ => C₁/V₁ = C₂/V₂

2. 50-Turn Electromagnet

a. Ratio of turns between electromagnets.

50-Turn EM : 25-Turn EM => 2:1 ratio of turns between electromagnets

b. Ratio of Paperclips Picked UP

Between maximum voltage and minimum voltages for 50-Turn EM

=> 47 clips (6v) : 13 clips (1.5v) => 3.6:1 ratio...

That is, the 6v battery-EM, on the average, picks up 3.6x more clips than the 1.5v battery-EM given 50-Turn EM.

3. Doubling number of coils:

Doubling the number of coils, on the average, doubles the number of clips picked up by either electromagnet.

Voltage 50-Turn EM 25-Turn EM Pick Up Ratio

1.5v 13 6 2:1

3.0v 26 12 2:1

4.5v 31 15.5 2:1

6.0v 47 23 2:1

4. Doubling Voltages:

Doubling voltage doubles the number of clips picked up by a given electromagnet regardless of the number of coils associated with magnet.

25-Turn EM Voltage Clips Pkd UP

1.5v 6

3.0v 12

Double voltage => Doubles # clips picked up*

50-Turn EM Voltage Clips Pkd UP

1.5v 13

3.0v 26

Double voltage => Doubles # clips picked up*

*Double Voltage => Double #clips picked up regardless of number of coil turns in electromagnet.

5. Predicting number of clips for 7.5v battery-EM

Using linear trendline equations shown on attached graphs...

#clips 50-Turn EM = 7.1333V + 2.5 = 7.1333(7.5) + 2.5 ≅ 56 clips

#clips 25-Turn EM = 3.6333V + 0.5 = 3.6333(7.5) + 0.5 ≅ 27 clips

Overall => 2:1 ratio of clips between 50-Turn EM and 25-Turn EM

6. Slope values based upon trendline equations shown on attached graphs are ...

25 Turn EM => slope = 3.6333

50 Turn EM => slope = 7.1333

Approximately a 2x increase upon doubling the number of coils of electromagnet.

Predicting number of clips for 1V electromagnets:

#Clips (1volt) 25-Turn EM = 3.6333(1) + 0.5 = 3.6833 ≅ 4 clips

#Clips (1volt) 50-Turn EM = 7.1333(1) + 2.5 = 9.6333 ≅ 10 clips

Shows to be consistent with double #clips with double number of coil turns.

6 0

3 years ago