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Stella [2.4K]
3 years ago
10

When a falling object reaches a speed called terminal velocity, its speed no longer increases. the object is losing gravitationa

l potential energy but not gaining kinetic energy. since energy must be conserved, where must the gravitational potential energy be going?
Physics
1 answer:
Ronch [10]3 years ago
8 0
As far as I know, the energy just winds up as heat dispersing into the atmosphere or heating up the falling object.
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15 POINTS! What is the function of the nervous system? What is the basic unit of the nervous system?
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The nervous system is a complex collection of nerves and specialized cells known as neurons that transmit signals between different parts of the body.

The somatic system consists of nerves that connect the brain and spinal cord with muscles and sensory receptors in the skin.

The basic unit of the nervous system is the "nerve cell," called "neuron

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4 years ago
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If forces acting on an object are unbalanced, which factor may result from an unbalanced force? The net force is negative. There
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Jeffery gains super strength and pushes two different objects with the same amount of force. Object A accelerates at 40 m/s2, an
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Answer: Object B

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5 0
4 years ago
I don’t know this one I need help
nikdorinn [45]
D
Using the kinetic energy 1/2mv^2 formula
5*10^5 is the answer
4 0
2 years ago
slader the cross section of a 5-ft long trough is an isosceles trapezoid with a 2 foot lower base, a 3-foot upper base, and an a
Ostrovityanka [42]

Answer:

0.08 ft/min

Explanation:

To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.

So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth <em>d</em> and the other (lets call it <em>l</em>) is given by:

l=\frac{3-2}{2}\,ft+2\,ft\\l=2.5\,ft

since the difference between the upper and lower base is the increase in the base and we are only at halft the height.

Now we can calculate the longitudinal section <em>A</em> at that point:

A=d\times l\\A=5\,ft \times 2.5\, ft\\A=12.5\, ft^{2}

And the raising speed <em>v </em>of the water is given by:

v=\frac{q}{A}\\v=\frac{1\, \frac{ft^3}{min}}{12.5\, ft^2}\\v=0.08\, \frac{ft}{min}

where <em>q</em> is the water flow (1 cubic foot per minute).

7 0
4 years ago
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