A circuit consists of a series combination of 5.50 âkΩ and 5.00 âkΩ resistors connected across a 50.0-V battery having negligi
ble internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 5.00 âkΩ resistor using a voltmeter having an internal resistance of 10.0 kΩ.1. What potential difference does the voltmeter measure across the 5.00 âkΩ resistor?2. What is the true potential difference across this resistor when the meter is not present?3. By what percentage is the voltmeter reading in error from the true potential difference?
1 answer:
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The charges have opposite sign and magnitude
Explanation:
The magnitude of the electrostatic force between two electric charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have:
F = 3.60 N is the force between the two charges
r = 30 cm = 0.30 m is their separation
The two charges have same magnitude, so
So we can rewrite the equation as
And solving for q:
Moreover, the force between the charges is attractive: we know that charges of same sign repel each other while charges of opposite sign attract each other, therefore the charges in this problem have opposite sign, so
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Answer:
5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity
Explanation:
The concept to solve this problem is given by Energy Transferred, the equation is given by,
Where,
Q= Energy transferred
m = mass of water
c = specific heat capacity
Temperature change (K or °C)
Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,
Then we can calculate the heat absorbed by m grams of ice at 0°C, then
How Q_1=Q_2, so
Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity