1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fiesta28 [93]
4 years ago
7

A circuit consists of a series combination of 5.50 âkΩ and 5.00 âkΩ resistors connected across a 50.0-V battery having negligi

ble internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 5.00 âkΩ resistor using a voltmeter having an internal resistance of 10.0 kΩ.1. What potential difference does the voltmeter measure across the 5.00 âkΩ resistor?2. What is the true potential difference across this resistor when the meter is not present?3. By what percentage is the voltmeter reading in error from the true potential difference?

Physics
1 answer:
omeli [17]4 years ago
7 0

Answer:

(a) 18.87 V

(b) 23.81 V

(c) 20.75%

Explanation:

The answers are given in the pictures. I have attached the pictures because circuits were needed to be drawn which are easier to understand when done on page. The page are numbered on top left corner.

You might be interested in
Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
julsineya [31]

Answer:

U=50.96J

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

U=3×1/4π∈₀×(q²/r)

Substitute given values

So

U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\  U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\  U=50.96J

8 0
3 years ago
What type of relationship exists between acceleration and mass?
likoan [24]
Here, you can derive that by numerical method, as follows:
F = m.a
m = F/a

So, here we can see when we decrease one, other increase by same effect; we can say they are "Indirectly Proportional" to each other!

Hope this helps!
7 0
3 years ago
(1) find the density of a substance if the mass of the substance is 150kg and dimension 20mby10mby5m
Vikentia [17]

Answer:

0.15kg/m³

Explanation:

Density = mass/ volume

Given that

Mass = 150kg

Note that volume = length x breadth x height

Volume = 20 x 10 x 5

Volume = 1000m³

Density = mass ➗ volume

Density = 150kg ➗ 1000m³

Density = 0.15kg/m³

I hope this was helpful, Please mark as brainliest  

3 0
3 years ago
Which term describes this diagram
STALIN [3.7K]

Answer:

the answer is letter; C

Explanation:

4 0
3 years ago
Read 2 more answers
Sjskskszpd no djdkzsnkakzx d
Mazyrski [523]

Answer:

jadjsakdjadkjadhfmafkj

Explanation:

:)

4 0
3 years ago
Other questions:
  • Vector a s is 2.80 cm long and is 60.0° above the x-axis in the first quadrant. vector b s is 1.90 cm long and is 60.0° below th
    12·1 answer
  • How can friction help you in your daily life?
    15·2 answers
  • A man stands on a scale in an elevator as shown here. the force of his weight when the elevator is still is fg downward. suppose
    7·1 answer
  • Astronomersestimatethata2.0-km-diameterasteroidcollides with the Earth once every million years. The collision could pose a thre
    7·2 answers
  • If an object is not accelerating, then one knows for sure that it is_____.​
    5·1 answer
  • Describe how fallacies can be created and spread
    12·1 answer
  • I need help!!! What is the answer!!
    8·1 answer
  • PLZZZZ HELP ME FOR BRAINLIEST AND 100 POINTS!!!!!!!
    14·2 answers
  • If the pH of a substance is 12.4, the substance is a _______
    14·1 answer
  • Which of these organs is an endocrine structure?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!