The slope at point A of the graph given below is:<br><br><br> WILL MARK BRAINLIEST TO CORRECT ANSWER

There are four springs stretched by the same mass.

kirill115 [55]

Answer:

That would be Spring C

Explanation:

i took the test :P

6 0

4 years ago

A 5.50 kg sled is initially at rest on a frictionless horizontal road. The sled is pulled a distance of 3.20 m by a force of 25.

kiruha [24]

(a) 69.3 J

The work done by the applied force is given by:

$W=Fd cos \theta$

where:

F = 25.0 N is the magnitude of the applied force

d = 3.20 m is the displacement of the sled

$\theta=30^{\circ}$ is the angle between the direction of the force and the displacement of the sled

Substituting numbers into the formula, we find

$W=(25.0 N)(3.20 m)(cos 30^{\circ})=69.3 J$

(b) 0

The problem says that the surface is frictionless: this means that no friction is acting on the sled, therefore the energy dissipated by friction must be zero.

(c) 69.3 J

According to the work-energy theorem, the work done by the applied force is equal to the change in kinetic energy of the sled:

$\Delta K = W$

where

$\Delta K$ is the change in kinetic energy

W is the work done

Since we already calculated W in part (a):

W = 69.3 J

We therefore know that the change in kinetic energy of the sled is equal to this value:

$\Delta K=69.3 J$

(d) 4.9 m/s

The change in kinetic energy of the sled can be rewritten as:

$\Delta K=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$ (1)

where

Kf is the final kinetic energy

Ki is the initial kinetic energy

m = 5.50 kg is the mass of the sled

u = 0 is the initial speed of the sled

v = ? is the final speed of the sled

We can calculate the variation of kinetic energy of the sled, $\Delta K$ , after it has travelled for d=3 m. Using the work-energy theorem again, we find

$\Delta K= W = Fd cos \theta =(25.0 N)(3.0 m)(cos 30^{\circ})=65.0 J$

And substituting into (1) and re-arrangin the equation, we find

$v=\sqrt{\frac{2 \Delta K}{m}}=\sqrt{\frac{2(65.0 J)}{5.50 kg}}=4.9 m/s$

6 0

4 years ago

What is a statement that’s summarizes a pattern found in nature

sergey [27]

The answer to your question is,

A scientific law.

-Mabel <3

5 0

3 years ago

Read 2 more answers

Putting a beaker of water in a microwave and turning it on for a minute or two will increase the temperature of the water. Descr

Jobisdone [24]

Answer:

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made

Explanation:

The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.

The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The main precaution that must be taken is not to open the microwave while it is on.

4 0

3 years ago

What would happen if you put bubble wrap around an experiment of heat energy

Makovka662 [10]

Answer: The air pressure would build up resulting in a high air density.

Explanation: Heat energy builds up air pressure. And if you surround it with bubble wrap, that air pressure will have nowhere to release to. And so because of that, high air density occurs.

3 0

3 years ago

The slope at point A of the graph given below is: WILL MARK BRAINLIEST TO CORRECT ANSWER