The slope at point A of the graph given below is: WILL MARK BRAINLIEST TO CORRECT ANSWER

A small button placed on a horizontal rotating platform with diameter 0.520 m will revolve with the platform when it is brought

yawa3891 [41]

For the position of button we can use force balance as

Friction Force = Centripetal force

so here we will have

$\mu_s mg = m\omega^2 R$

here we know that

R = radius of circle where button is placed

$\omega = 2\pi f$

f = 35 rev/min

$f = \frac{35}{60} rev/s = 0.58 rev/s$

$\omega = 2\pi (0.58) = 3.66 rad/s$

now from above equation

$\mu_s(m)(9.81) = (3.66)^2(0.240)$

$\mu_s = 0.33$

so friction coefficient will be 0.33

5 0

4 years ago

Given an object's mass and observing its acceleration, what can be found in a direct application of Newton's second law of motio

Natalka [10]

Answer:

C. the net force on the object

Explanation:

That is because Force= mass x acceleration. The question says that we know the mass and acceleration, which means that it would be the force that resulted in the acceleration of the mass.

6 0

3 years ago

Jalen combines two substances in science class. Once combined, only one of the two substances

dusya [7]

Answer: b. The combination is a mixture because the substances can be separated

Explanation: Based on the facts presented above, the combination of both both substances can be referred to as a mixture due to the following:

A mixture is obtained when two or more substances or materials are combined without a chemical reaction. This is observed when Jalen combined substance 1 and 2 with only one of the substances becoming visible after the combination.

The other reason is that, a mixture can be separated back into its original constituent, this is evident when the combination was filtered with only substance 2 going through the filter and substance 1 remaining in the filter

4 0

3 years ago

A car of mass m, traveling at constant speed, rides over the top of a round hill. How do the normal force of the road on the car

dybincka [34]

Answer:

The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is option B.

Explanation:

Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:

At the top of a round hill

$Normal force = Gravitational force - centripetal force$

At the foot of a round hill

$Normal Force = centripetal force + Gravitational force$

4 0

4 years ago

A particle of mass 7.00 10-8 kg and charge 7.8-µc is traveling due east. it enters perpendicularly a magnetic field whose magnit

sertanlavr [38]

The radial force on the particle is given by the Lorentz force. They don't give you the velocity so you have to solve for it in terms of the radius and get them to cancel.

6 0

3 years ago