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4 years ago

Rank planets left to right based on distance from the sun

Physics

2 answers:

3241004551 [841]4 years ago

5 0

from farthest to the nearest

Neptune

Uranus

saturn

Jupiter

mars

earth

venus

mercury

lidiya [134]4 years ago

5 0

Answer:

I mean since this is just telling where the normal line of the planets is and not a Jovian etc.

Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune

Explanation:

It's just asking the order from smallest to greatest. Just flip it the other direction if it's largest to smallest.

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Read 2 more answers

A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

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3 years ago

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