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3241004551 [841]

3 years ago

12

Rank planets left to right based on distance from the sun

2 answers:

3241004551 [841]3 years ago

5 0

from farthest to the nearest

Neptune

Uranus

saturn

Jupiter

mars

earth

venus

mercury

lidiya [134]3 years ago

5 0

Answer:

I mean since this is just telling where the normal line of the planets is and not a Jovian etc.

Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune

Explanation:

It's just asking the order from smallest to greatest. Just flip it the other direction if it's largest to smallest.

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A plane flying horizontally at a speed of 50 m/s and at an elevation of 160 m drops a package, and 2.0 s later it drops a second

Anarel [89]

Answer:

386 m

Explanation:

Let's call the horizontal distance between the point of launch and the point of landing of the first package $x\text{ m}$ .

2 seconds after landing at $x$ , the plane has travelled a horizontal distance of $2\text{ s}\times 50 \text{ m/s} = 100\text{ m}$ .

At this new point, the second package is launched. Because it is launched under the same conditions as the first, its horizontal distance from its point of launch is also $x\text { m}$ .

To determine $x$ , we determine the time of fall of the package. Being a vertical motion, the drop has an initial velocity, $u$ , of 0 m/s with acceleration, $a = g = 9.8 \text{ m/s}{}^2$ , and a distance, $s$ , of 160 m. We use the equation of motion:

$s = ut+\frac{1}{2}at^2$

$160 = 0\times t + \frac{1}{2}9.8\times t^2$

$t = \sqrt{\dfrac{160}{4.9}}\text { s}=\dfrac{40}{7}\text { s}$

In this time, the package, with a horizontal velocity of 50 m/s, travels the horizontal distance, $x$ , of

$x = 50 \text{ m/s}\times \dfrac{40}{7}\text { s} = \dfrac{2000}{7}\text { m} = 286 \text{ m}$

The distance apart between both packages is $x+100\text{ m} = 286+100\text{ m} = 386\text{ m}$

7 0

3 years ago

How does time relate to motion

docker41 [41]

As we move, time goes up. Think of it on a graph; as time increases on the x axis, motion can either stay the same, increase, or decrease.

5 0

2 years ago

In a power plant, pipes transporting superheated vapor are very common. Superheated vapor flows at a rate of 0.3 kg/s inside a p

grigory [225]

Answer: $h=160.84 W/m^2-K$

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

Inside temperature=22

Pipe surface =100

Temperature drop=30

specific heat of vapor(c)=2190 J/kg.k

heat supplied $Q=mc\Delta T=0.3\times 2190\times (30)$

Heat due to convection =hA(100-30)

$A=\pi d\cdot L$

$A=\pi 0.05\times 10=1.571 m^2$

$Q_{convection}=h\times 1.571\times (100-22)=122.538 h$

$Q=Q_{convection}$

19,710=122.538 h

$h=160.84 W/m^2-K$

5 0

3 years ago

A simple pendulum on the surface of Earth is found to undergo 15.0 complete small‑amplitude oscillations in 8.75 s. Find the pen

FinnZ [79.3K]

Answer:

Length of the Pendulum is 14.4 cm

Explanation:

Time period of simple pendulum is given by

$T=2\pi \sqrt{\frac{L}{g} } \\$

time taken for one oscillation is

$T=\frac{time taken}{oscillations} \\T=\frac{8.75}{15} \\T=0.583 s$

Pendulum length on the earth surface is

$L=\frac{T^2g}{4\pi^2 }\\L=\frac{0.583\times 9.8}{4\pi^2 } \\L=0.144 m$

Length of the Pendulum is 14.4 cm

6 0

4 years ago

Cars A and B are racing each other along the same straight road in the following manner:

zysi [14]

Answer:

$\frac{x_{o}}{v_B-V_A} =t$

Explanation:

Represent the car's position as a function

$x_o=$ "head start"

$x_{A}(t) = x_{o} + v_{A}t\\x_B(t)=v_Bt \\$

$Remember: v_B>v_A$

"cathching up means" that $x_A(t)=x_B(t)$

$x_{o} + v_{A}t =v_Bt\\x_{o} = v_Bt -v_{A}t\\x_{o} = t(v_B-V_A)\\\frac{x_{o}}{v_B-V_A} =t, where \ v_B>v_A$

8 0

3 years ago