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GuDViN [60]
3 years ago
9

Sorry all but I have been working on this one for a little bit no clue what so every on this one so lost please help thank you

Mathematics
1 answer:
kiruha [24]3 years ago
8 0
It's B. If you draw those 2 points and then connect them together they will form a rectangle. 
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-v + 5 + 6v = 1 + 5v + 3
Dima020 [189]

Answer:

v does not exist

Step-by-step explanation:

5v+5=4+5v

there is no v

5 0
3 years ago
Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is
professor190 [17]
Ok, here we go.  Pay attention.  The formula for the arc length is AL= \int\limits^b_a { \sqrt{1+( \frac{dy}{dx})^2 } } \, dx.  That means that to use that formula we have to find the derivative of the function and square it.  Our function is y = 4x-5, so y'=4.  Our formula now, filled in accordingly, is AL= \int\limits^2_1 { \sqrt{1+4^2} } \, dx (that 1 is supposed to be negative; not sure if it is til I post the final answer).  After the simplification we have the integral from -1 to 2 of \sqrt{17}.  Integrating that we have AL= \sqrt{17}x from -1 to 2.  2 \sqrt{17}-(-1 \sqrt{17} ) gives us 3 \sqrt{17}.  Now we need to do the distance formula with this.  But we need 2 coordinates for that.  Our bounds are x=-1 and x=2.  We will fill those x values in to the function and solve for y.  When x = -1, y=4(-1)-5 and y = -9.  So the point is (-1, -9).  Doing the same with x = 2, y=4(2)-5 and y = 3.  So the point is (2, 3).  Use those in the distance formula accordingly: d= \sqrt{(2-(-1))^2+(3-(-9))^2} which simplifies to d= \sqrt{9+144}= \sqrt{153}.  The square root of 153 can be simplified into the square root of 9*17.  Pulling out the perfect square of 9 as a 3 leaves us with 3 \sqrt{17}.  And there you go!
5 0
2 years ago
On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to
Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = (21-11) \ million = 10 million

1960-1970 = (41-21)\ million = 20 million

1970-1980 = (71-41)\ million = 30 million

1980-2000 = (161-71)\ million= 90 million

Rate of change (1950-1960)= \frac{10}{11} \times 100= 90.90\%

Rate of change (1960-1970) = \frac{20}{21} \times 100= 95.23\%

Rate of change (1970-1980)=  \frac{30}{41} \times 100= 73.17\%

Rate of change (1980-2000)= \frac{90}{71} \times 100= 126.76\%

∴ rate of change between 1980 to 2000 is 126.78%

7 0
3 years ago
is x-1 taking away an x or adding an x?? im trying to find the perimeter of area tiles, and the perimeter is x + x + x + (x-1) +
Vanyuwa [196]

Answer:

4x + 2

Step-by-step explanation:

x - 1 is adding an x and subtracting a 1 ,so

x + x + x + (x - 1) + 1 + 1 + 1

= x + x + x + x - 1 + 1 + 1 + 1 ← collect like terms

= 4x + 2

3 0
2 years ago
Which two triangles are congruent? Complete the congruence statement. ​
andre [41]

answer:

△JKI ≅ △CED

step-by-step explanation:

  • like i mentioned before, they look similar and fulfill the SSS triangle theorem (this time's the theorem is different only)
4 0
3 years ago
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