Answer:
A and F i think
Explanation:
Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all lower than that of the pure solvent and is directly proportional to the molality of the solute
Answer:
Acetic acid is a weak acid because it partially dissociates into its constituent ions when dissolved in water. This weak acid is known to form miscible mixtures with water. An acetic acid is an acid that ionizes only slightly in an aqueous solution. Therefore it's a weak acid.
Hope that helps. x
Answer: 365 K
Explanation:
According to the Arrhenius equation,
or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 
= 1.00
= rate constant at 
= 5.00
= activation energy for the reaction = 28.90 kJ/mol= 28900 j/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 313 K
= final temperature = ?
Now put all the given values in this formula, we get
![\log (\frac{5.00}{1.00})=\frac{28900}{2.303\times 8.314J/mole.K}[\frac{1}{313K}-\frac{1}{T_2K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B5.00%7D%7B1.00%7D%29%3D%5Cfrac%7B28900%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B313K%7D-%5Cfrac%7B1%7D%7BT_2K%7D%5D)
![0.69=\frac{28900}{2.303\times 8.314J/mole.K}[\frac{1}{313K}-\frac{1}{T_2K}]](https://tex.z-dn.net/?f=0.69%3D%5Cfrac%7B28900%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B313K%7D-%5Cfrac%7B1%7D%7BT_2K%7D%5D)
Therefore, 365 K is required to increase the reaction rate by 5.00 times.
Answer:
97 J
Explanation:
Step 1: Given data
- Mass of the sample (m): 12 kg
- Specific heat capacity (c): 0.231 J/kg.°C (this can also be expressed as 0.231 J/kg.K)
- Initial temperature: 45 K
Step 2: Calculate the temperature change
ΔT = 80 K - 45 K = 35 K
Step 3: Calculate the heat required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.231 J/kg.K × 12 kg × 35 K = 97 J
