I think C-I
It can also be wrong but that’s my opinion
Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
Answer:
Boron and Aluminium
Explanation:
Boron and Aluminium are present in Group 13 of the modern periodic table. Group 13 (IUPAC System) can also be referred to as Group III-A. Logically, Boron and Aluminum can't be placed alongwith elements such as Yttrium as they don't exhibit properties of a transition metal.
Answer:
16.6dL
Explanation:
First, we need to convert 1.66mL dL this can be achieved by doing the following:
1mL = 0.01dL
1.66mL = 1.66 x 0.01 = 0.0166dL
From the question, we were told that the volume 1 drop of blood = 1.66mL i.e 0.0166dL.
Therefore 1000 drops of blood will be = 0.0166 x 1000 = 16.6dL
Answer:
2.677 J/g°C
Explanation:
Quantity of heat required to raise the temperature of the metal,
Q = mc∆T
where m is the mass of the metal, c is the metal's specific heat capacity, and ∆T is the change in temperature that accompanies the heat transfer process
20.0J = 50.0g × c × 150°C
c = 20.0J/(50.0g × 150°C)
c = 2.677 J/g°C
