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3 years ago

What does the number of valence electrons determine?

1 answer:

N76 [4]3 years ago

4 0

Valence electrons are the electrons in the outermost shell of an element on the periodic table. Atoms want to be able to have a full outer shell and they can share or trade electrons in order to achieve this. Valence electrons are also super super important in chemical reactions. The number of valence electrons determines what group that specific atom or element is in on the periodic table. This affects the reactivity of the element.

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What is work and state the law of conservation mass?<br>

Butoxors [25]

Answer:

Work is a force causing the movement or displacement of an object

law of conservation mass:

1. Atoms cannot be created or destroyed in a chemical reaction.

2. Molecules cannot be created or destroyed in a chemical reaction.

3. Compounds cannot be created or destroyed in a chemical reaction.

4. Heat cannot be created or destroyed in a chemical reaction.

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3 years ago

Identify each definition that applies to the compound in red. Check all that apply.

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Answer:

Arrhenius acid & Bronsted-Lowry acid

Explanation:

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3 years ago

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3 years ago

The vapor pressure of a liquid __________.

mash [69]

Answer:

Explanation:

The tendency of a liquid to convert to vapour increases smoothly with increasing temperature. Vapour pressure shows the tendency of a liquid to convert to vapour. Increase In vapour pressure shows an increased tendency to convert to vapour. The higher the temperature, the higher the vapour pressure.

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3 years ago

Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 7.9 g of methane is

Vikki [24]

Explanation:

The given reaction is as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

As it is known that number of moles equal mass divided by molar mass. Molar mass of methane is 16 g/mol.

Hence, No. of moles = $\frac{mass}{molar mass}$

= $\frac{7.9 g}{16 g/mol}$

= 0.493 mol

Molar mass of oxygen is 32 g/mol.

Hence, its number of moles = $\frac{mass}{molar mass}$

= $\frac{14.4 g}{32 g/mol}$

= 0.45 mol

As, it is shown from the reaction that 1 mole of methane needs 2 mole of oxygen.

Therefore, 0.493 mol of methane needs $2 \times 0.45 mol$ equals 0.9 moles of oxygen.

As there is only 0.45 moles of oxygen for the reaction. So, it means that oxygen is the limiting reagent.

Hence, for 0.45 moles of oxygen, methane required is as follows.

$\frac{0.45}{2}$ = 0.225 moles

So, 0.225 moles of methane is equal to $0.225 \times 16$ = 3.6 g

As, 3.6 g of methane reacts with oxygen. Therefore, amount of methane remains is calculated as follows.

(7.9 g - 3.6 g) = 4.3 g

Thus, we can conclude that the minimum mass of methane that could be left over by the chemical reaction is 4.3 g.

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3 years ago