Answer:
Hi, even though this is really not a question or an answer to a question.
Explanation:
Do you know if any of this stuff involves 6th grade?
Answer:
3 years
Explanation:
Given data:
Initial amount of sample = 160 Kg
Amount left after 12 years = 10 Kg
Half life = ?
Solution:
at time zero = 160 Kg
1st half life = 160/2 = 80 kg
2nd half life = 80/2 = 40 kg
3rd half life = 40 / 2 = 20 kg
4th half life = 20 / 2 = 10 kg
Half life:
HL = elapsed time / half life
12 years / 4 = 3 years
Answer:
The number of moles of O atom in 
mol of 
= 1.6
Explanation:
1 molecule of contains 2 atoms of O
So, 
molecules of contains 
atoms of O.
We know that 1 mol of an atom/molecule/ion represents 
numbers of atoms/molecules/ions respectively.
So, molecules of is equal to 1 mol of .
atoms of O is equal to 2 moles of O atom.
Hence, 1 mol of contains 2 moles of O atom.
Therefore, mol of contains 
moles of O atom or 1.6 moles of O atom.
<span>polar, Hadley, Ferrel, polar, Hadley, Ferrel. I hope this helps you.</span>
Answer:
132g/mole
Explanation:
using the formula PV=nRT should be used to solve for the number of moles (n). R is a constant which is 62.3637 L mmHG/mole K.
Inorder for your units to match you will have to convert 125ml to .125L and the temperature of 85C to K . you do that by adding 273 to the 85C and get 358K. Once you solve for n then you use that number and divide by the number of grams from the question (.560g) since molar mass is grams/moles.
