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3 years ago

Y =4X +2 , y =2(2x -1)

Mathematics

1 answer:

Brums [2.3K]3 years ago

6 0

Answer:

y =4x +2, y =4x-2

Step-by-step explanation:

according to this step we are not collecting like terms

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A survey with a two-point scale was conducted in an organization. It concluded that 85% of the respondents were unsatisfied with

Morgarella [4.7K]

Answer:

Number of the peoples were satisfied with the career guidance are 300 .

Step-by-step explanation:

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

A survey with a two-point scale was conducted in an organization.

It concluded that 85% of the respondents were unsatisfied with the career guidance they were provided.

If 2,000 people participated in the survey.

Total value = 2000

Percentage = 85%

Putting all the values in the formula

$85 = \frac{Part\ value\times 100}{2000}$

$Part\ value= \frac{2000\times 85}{100}$

$Part\ value= \frac{170000}{100}$

Part value = 1700

i.e

People not satisfied by the career guidance = 1700

People satisfied by the career guidance = Total people participated in survey - People not satisfied by the career guidance .

Putting the values in the above

= 2000 - 1700

= 300

Therefore the number of the peoples were satisfied with the career guidance are 300 .

5 0

3 years ago

Read 2 more answers

I will give you a little brainliest

aalyn [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What expression is equivalent to (9x^2 + 2x -7)(x - 4)

Dima020 [189]

Answer: C

Step-by-step explanation:

We can use the expanding rule to get that one if the expressions is

(9x^2 + 2x - 7)x + (9x^2 + 2x - 7)(-4)

3 0

2 years ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0

3 years ago

Equation of a line with slip of 5 passing through points (-4,-6)

kirill [66]

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=5[x-(-4)] \\\\\\ y+6=5(x+4)\implies y+6=5x+4\implies y=5x-2$

5 0

3 years ago