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Blizzard [7]
3 years ago
14

A 7.0 kg mess kit sliding on a frictionless surface explodes into two 3.5 kg parts, one moving at 5.5 m/s, due north, and the ot

her at 7.5 m/s, 30° north of east. What was the original speed of the mess kit? m/s
Physics
1 answer:
IRISSAK [1]3 years ago
3 0

Answer:

The original speed of the mess kit is 5.65 m/s.

Explanation:

Given that,

Mass of kit =7.0 kg

Mass of first = 3.5 kg

Speed= 5.5 m/s

Speed of other particle part = 7.5 m/s

Angle = 30°

We need to calculate the momentum of first part

Using formula of momentum

P=mv

Put the value into the formula

P_{1}=3.5\times5.5j

P_{1}=19.25j\ kgm/s

We need to calculate the momentum of second part

Using formula of momentum

P_{2}=3.5\times7.5(\cos30i+\sin30j)

P_{2}=26.25\times\dfrac{\sqrt{3}}{2}i+26.25\times\dfrac{1}{2}j

P_{2}=22.73i+13.13j

We need to calculate the total momentum

P=P_{1}+P_{2}

P=19.25j+22.73i+13.13j

P=22.73i+32.38j

P=\sqrt{(22.73)^2+(32.38)^2}

P=39.56\ kgm/s

We need to calculate the original speed of the mess kit

Using formula of momentum

P=MV

V=\dfrac{P}{M}

Put the value into the formula

V=\dfrac{39.56}{7.0}

V=5.65\ m/s

Hence, The original speed of the mess kit is 5.65 m/s.

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So, when both the charges are carry the same charge and r is small then the value of potential energy will be positive in nature.

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