The answer to the question 3.51
Answer: 6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.
step by step explanation:
\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}
Solution-
The quadratic function is,
6x^2-24x + 1
a = 6, b = -24, c = 1
x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}
=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}
=\dfrac{24\pm \sqrt{576-24}}{12}
=\dfrac{24\pm \sqrt{552}}{12}
=\dfrac{24\pm 2\sqrt{138}}{12}
=\dfrac{12\pm \sqrt{138}}{6}
=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}
Answer:
F(2x+3) = 12/(2x+3) +1/2
Step-by-step explanation:
Put the argument of the function where the variable is. You can simplify if you want, but the original function definition is not simplified, so we assume it is not required.
F(x) = 12/x + 1/2
Put (2x+3) where x is:
F(2x+3) = 12/(2x+3) + 1/2
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<em>Comment on the function</em>
If you intend f(x) = 12/(x +1/2), then you would do the same thing: put (2x+3) where x is. In this case, you could combine the +3 and the +1/2, if you want.
... F(2x+3) = 12/((2x+3) +1/2) = 12/(2x +3.5)
Answer:
5/4 and 6/3
Step-by-step explanation:
Your taking one away from denominator and adding it to numerator
Answer:
f(5) = 2
Step-by-step explanation:
<u>Given: </u>
- Function f(x) =
<u>For x=5 :</u>
- f(5) = = = 2