The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
To find the answer, we have to know more about the basic forces acting on a body.
<h3>How to find the net force on the box?</h3>
- Let us draw the free body diagram of the given box with the data's given in the question.
- From the diagram, we get,
where, N is the normal reaction, mg is the weight of the box, 
is the net force, f is the kinetic friction.
- We have the expression for kinetic friction as,
- Thus, the net force will be,
Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
Learn more about the basic forces on a body here:
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Answer:
a) The potential energy in the system is greatest at X.
Explanation:
Let be X the point where a ball rests at the top of a hill. By applying the Principle of Energy Conservation, the total energy in the physical system remains constant and gravitational potential energy at the top of the hill is equal to the sum of kinetic energy, a lower gravitational energy and dissipated work due to nonconservative forces (friction, dragging).
Conclusions are showed as follows:
a) The potential energy in the system is greatest at X.
b) The kinetic energy is the lowest at X and Z.
c) Total energy remains constant as the ball moves from X to Y.
Hence, the correct answer is A.
Answer:
F = 0.64 N
Explanation:
We are given;
Spring constant constant; k = 1.28 N/m
Distance; x = 0.5 m
From Hooke's law, we know that F = kx.
Thus;
F = 1.28 × 0.5
F = 0.64 N
Thus, force it takes to pull the spring back = 0.64 N
Answer:
Moving the magnet away from the center of the loop with its south pole facing the center of the loop.
Explanation:
Electromagnetic induction is due to a rapidly changing magnetic field, or loop area. The poles of the magnet induce current in the loop but in the opposite direction, depending on the direction of their relative motion. An approaching north pole will induce an anticlockwise current in the loop, while an approaching south pole will do the reverse. To get the galvanometer to flicker in the same direction as of that when the north pole was approaching, we move the magnet away from the center of the loop with its south pole facing the center of the loop.
360 degrees. I'm pretty sure
