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3 years ago

How many degrees does the earth revolve in a day ?

Physics

2 answers:

kakasveta [241]3 years ago

6 0

360 degrees. I'm pretty sure

Rom4ik [11]3 years ago

6 0

<span> 360.9856 degrees, the world revolves around 360 degrees every 24 hours

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You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s

Amiraneli [1.4K]

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

$W = \dfrac{1}{2}kx^2$

$5 = \dfrac{1}{2}kx^2$ ............(1)

Work done in compression of spring at higher setting

$W' = \dfrac{1}{2}kx'^2$

$W'= \dfrac{1}{2}k(2x)^2$

$W'= 4\times \dfrac{1}{2}kx^2$

$W'= 4\times W$

from equation (1)

$W'= 4\times 5$

W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

4 0

3 years ago

A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distancer1

Jobisdone [24]

Answer:

The magnitude of the electric field in the second case will be $\frac{1}{8}$ of the electric field in the first case

Explanation:

The electric field at a distance $r_1$ < R from the center of the sphere is given by

the formula $E_1$ = $\frac{kQr_1}{R^3}$

where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.

It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance $r_1$ from the center.

In the second case the electric field will be given by

$E_2$ = $\frac{kQr_1}{(2R)^3} = \frac{kQr_1}{8R^3} =\frac{1}{8} \frac{kQr_1}{R^3} = \frac{1}{8} E_1$

Therefore the magnitude of the electric field in the second case will be $\frac{1}{8}$ of the electric field in the first case.

4 0

3 years ago

A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of 5.0 m/s, hoping to land on the roof of

lisabon 2012 [21]

Answer:

D = 3.0 m

Explanation:

Assuming no other forces than gravity acting upon the criminal, his horizontal velocity must keep constant at 5.0 m/s.
So, the horizontal displacement, applying the definition of average velocity, is just:

$\Delta x = v_{h} * t (1)$

In the vertical direction, the criminal is in free fall, starting from rest.
Since we know the dfference in height between both roofs, we can use the kinematic equation for vertical displacement, as follows:

$\Delta h = \frac{1}{2} * g * t^{2} = 2.0 m$