is the period of orbit.
<u>Explanation:
</u>
The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:

Where,
T is the period of the orbit
R is the average radius of orbit
G is gravitational constant 
Here, given data


Substitute the given values, we get T as



Taking square root, we get

Answer: 8.1 x 10^24
Explanation:
I(t) = (0.6 A) e^(-t/6 hr)
I'll leave out units for neatness: I(t) = 0.6e^(-t/6)
If t is in seconds then since 1hr = 3600s: I(t) = 0.6e^(-t/(6 x 3600) ).
For neatness let k = 1/(6x3600) = 4.63x10^-5, then:
I(t) = 0.6e^(-kt)
Providing t is in seconds, total charge Q in coulombs is
Q= ∫ I(t).dt evaluated from t=0 to t=∞.
Q = ∫(0.6e^(-kt)
= (0.6/-k)e^(-kt) evaluated from t=0 to t=∞.
= -(0.6/k)[e^-∞ - e^-0]
= -0.6/k[0 - 1]
= 0.6/k
= 0.6/(4.63x10^-5)
= 12958 C
Since the magnitude of the charge on an electron = 1.6x10⁻¹⁹ C, the number of electrons is 12958/(1.6x10^-19) = 8.1x10^24 to two significant figures.
Frequency, υ = 2.09 Hz
We know that time period, T = 1/υ
∴ T = 1 ÷ 2.09
⇒ T = 0.4784 seconds
Answer:
Explanation:
mass of astronaut, M = 66.5 kg
mass of tool, m = 2.3 kg
velocity of tool, v = 3.10 m/s
Let the velocity of astronaut is V.
(A) According to the conservation of moemntum
Momentum of astronaut = Momentum of tool
M x V = m x v
66.5 x V = 2.3 x 3.10
V = 0.107 m/s
(B) The direction of motion of astronaut is opposite to the direction of motion of tool.
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