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valina [46]
2 years ago
6

Sharon the ant (Aaron’s sister) sits at the edge of a turntable of radius R that is spinning with period T. As she makes one-hal

f of a full rotation on the turntable, what is the magnitude of the average acceleration experienced by Sharon the ant?
Physics
1 answer:
Dmitry_Shevchenko [17]2 years ago
6 0

Answer:

a = \dfrac{4\pi^2R}{T^2}

Explanation:

The acceleration of a circular motion is given by

a = \omega^2 R

where \omega is the angular velocity and R is the radius.

Angular velocity is related to the period, T, by

\omega=\dfrac{2\pi}{T}

Substitute into the previous formula.

a = (\dfrac{2\pi}{T})^2 R

a = \dfrac{4\pi^2R}{T^2}

This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.

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A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
Delvig [45]

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

<h3>Work done by the applied force</h3>

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

<h3>Work done by frictional force</h3>

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

<h3>Net work done by all the forces on the tractor</h3>

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

4 0
1 year ago
Stomach acid is a dilute solution of hydrochloric acid (HCl). In this case the word dilute means
vfiekz [6]
I think the correct answer would be that there are a relatively small number of moles of HCl present. Dilute would mean that there are very few solute particles dissolved as compared to the solvent particles in the solution. Hope this helps.
6 0
3 years ago
Read 2 more answers
Why does a solid change to liquid when heat is added
marissa [1.9K]

heat excites molecules at their "lattice" sites. Enough to break the lattice bonds set the molecules free of each other and ... melt.

8 0
3 years ago
What side of the worm faces up when placed in the tray when dissection?
Lelechka [254]

<span>The side of the worm that faces up when placed in the tray for dissection is the smoother side.

</span>You can observe the organs of these tiny creatures by dissecting a preserved earthworm<span>. In dissecting a worm, </span><span>lay the worm on your </span>dissecting tray<span> <span>with its dorsal side facing up.</span></span>

8 0
3 years ago
A spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of
Rasek [7]

Answer:

a) (5.59 × 10³) N/C

b) 0.226 N directed away from the spider.

Explanation:

a) Electric field, E, felt as a result of point charge, Q, at a distance, d away is given by

E = kQ/d²

So, magnitude of the electric field due to the charge on the second spider at the position of the first spider

Q = 4.2 µC = 4.2 × 10⁻⁶ C

k = Coulomb's constant = 8.99 × 10⁹ Nm²/C

d = 2.6 m

E = (8.99 × 10⁹ × 4.2 × 10⁻⁶)/2.6²

E = 5.59 × 10³ N/C

b) Tension in the silk fiber above the spider is the net force due to the weight of spider one and the force of repulsion due the two charges.

Force due to the two charges = Eq

where q now represents the charge of the first spider at the first point, feeling the electric field calculated in (a)

F = 5.59 × 10³ × 3.4 × 10⁻⁶ = 0.01901 N directed upwards. (That is, F = + 0.019 N)

Weight of the spider = mg = 0.025 × 9.8 = 0.245 N directed downwards. (That is, W = -0.245 N)

Net force, T = mg - F = 0.245 - 0.019 = 0.226 N (that is, 0.226 N, directed upwards, away from the spider).

8 0
3 years ago
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