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valina [46]
3 years ago
6

Sharon the ant (Aaron’s sister) sits at the edge of a turntable of radius R that is spinning with period T. As she makes one-hal

f of a full rotation on the turntable, what is the magnitude of the average acceleration experienced by Sharon the ant?
Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

a = \dfrac{4\pi^2R}{T^2}

Explanation:

The acceleration of a circular motion is given by

a = \omega^2 R

where \omega is the angular velocity and R is the radius.

Angular velocity is related to the period, T, by

\omega=\dfrac{2\pi}{T}

Substitute into the previous formula.

a = (\dfrac{2\pi}{T})^2 R

a = \dfrac{4\pi^2R}{T^2}

This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.

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About 285 meters per minute
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3 years ago
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Which describes electricity?
SVETLANKA909090 [29]

Answer:

all of the above

Explanation:

- a build up of electric charge

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- an electric current

are three different ways to describe electricity.

So the answer is all of the above.

7 0
2 years ago
A gry is an old English measure for length, defined as 1/10 of a line, where line is another old English measure for length, def
Valentin [98]

Answer:

0.2448 point²

Explanation:

1 gry = 1/10 line

1 line = 1/12 inch

=> 1 gry in inches = 1/10 * 1/12 = 1/120 inch

=> 1 inch = 120 gry

1 point = 1/72 inch

=> 1 inch = 72 points

Therefore,

120 gry = 72 points

=> 1 gry = 3/5 point

Therefore,

1 gry² = (3/5)² point²

1 gry² = 9/25 point²

This means that 0.68 gry² will be:

0.68 gry² = 0.68 * 9/25 point²

=> 0.68 gry² = 0.2448 point²

6 0
3 years ago
Convert 1.5 radian into milliradians.
Alex

Answer:

1500 milliradians

Explanation:

Data provided in the question:

1.5 radians

Now,

1 radians consists of  1000 milliradians

1 milli = 1000

thus for the 1.5 radians, we have

1.5 radians = 1.5 multiplied by 1000 milliradians

or

1.5 radians = 1500 milliradians

Hence, after the conversion

1.5 radians equals to the value 1500 milliradians

4 0
3 years ago
A luge run is straight for the first 10 m. If the velocity of the luger when he passes the start line is +25 m/s and his acceler
dangina [55]
V^2 =U^2 +2AS
V^2 = 25 ^2 + 2x9.5x10
V^2 = 625 + 1900 = 2525
V = 50.25
3 0
3 years ago
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