We know, work done = Weight * Displacement
w = 3.76 * 2
w = 7.52 J
In short, Your Answer would be: 7.52 Joules
Hope this helps!
We see more and more of the lighted side of the moon.
you're welcome, m8
(1) You must find the point of equilibrium between the two forces,
<span>G * <span><span><span>MT</span><span>ms / </span></span><span>(R−x)^2 </span></span>= G * <span><span><span>ML</span><span>ms / </span></span><span>x^2
MT / (R-x)^2 = ML / x^2
So,
x = R * sqrt(ML * MT) - ML / (MT - ML)
R = is the distance between Earth and Moon.
</span></span></span>The result should be,
x = 3.83 * 10^7m
from the center of the Moon, and
R - x = 3.46*10^8 m
from the center of the Earth.
(2) As the distance from the center of the Earth is the number we found before,
d = R - x = 3.46*10^8m
The acceleration at this point is
g = G * MT / d^2
g = 3.33*10^-3 m/s^2
Acceleration is found if we have the force and mass.
With the following equation: F = ma, we can find the missing values.
F = 25n
M = 0.5 kg
a = ?
a = f/m
a = 25/0.5
a = 50
a = 50 m/s
So, the acceleration is 50 m/s^2
