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Mrac [35]
3 years ago
8

Acceleration equation physics

Physics
2 answers:
ella [17]3 years ago
7 0

Answer:

F=ma

dv/dt= a

a is referred to as acceleration

Rudiy273 years ago
7 0

Answer:

Acceleration=change in velocity ➗ time

Explanation:

Acceleration=change in velocity ➗ time

Whereby:

Change in velocity=final velocity - initial velocity

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gogolik [260]

Answer:

A. Zero

Explanation:

The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :

F = N * I * A * B * sinθ

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Since the normal of the area is parallel to the magnetic field, θ = 0

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F = NIABsin0

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3 0
3 years ago
What is a electron orbit?
Advocard [28]

the path of an electron around the nucleus of an atom

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A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
Lynna [10]

Explanation:

Given Data

Total mass=93.5 kg

Rock mass=0.310 kg

Initially wagon speed=0.540 m/s

rock speed=16.5 m/s

To Find

The speed of the wagon

Solution

As the wagon rolls, momentum is given as

P=mv

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m is mass

v is speed

put the values

P=93.5kg × 0.540 m/s

P =50.49 kg×m/s

Now we have to find the momentum of rock

momentum of rock = mv

momentum of rock = (0.310kg)×(16.5 m/s)

momentum of rock =5.115 kg×m/s  

From the conservation of momentum we can find the wagons momentum So

wagon momentum=50.49 -5.115 = 45.375 kg×m/s  

Speed of wagon = wagon momentum/(total mass-rock mass)

Speed of wagon=45.375/(93.5-0.310)

Speed of wagon= 0.487 m/s

Throwing rock backward,

momentum of wagon = 50.49+5.115 = 55.605  kg×m/s

Speed of wagon = wagon momentum/(total mass-rock mass)

speed of wagon = 55.605  kg×m/s/(93.5kg-0.310kg)

speed of wagon= 0.5967 m/s

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3 years ago
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The unit of height is:
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5 0
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harkovskaia [24]

Resistance = Voltage/Current

                   = 10/5

Resistance = 2 ohms

4 0
3 years ago
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