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Mrac [35]
3 years ago
8

Acceleration equation physics

Physics
2 answers:
ella [17]3 years ago
7 0

Answer:

F=ma

dv/dt= a

a is referred to as acceleration

Rudiy273 years ago
7 0

Answer:

Acceleration=change in velocity ➗ time

Explanation:

Acceleration=change in velocity ➗ time

Whereby:

Change in velocity=final velocity - initial velocity

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A tug-of-war game is played by five c/hildren: three on one team and two on the other. How much force will the two child team ha
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A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio
tatuchka [14]

Answer:

acceleration = 0.2625 m/s²

Explanation:

   acceleration = ( final velocity - initial velocity ) / time

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6 0
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Read 2 more answers
A spring gun is made by compressing a spring in a tube and then latching the spring at
inn [45]

Answer:

a)v=13.2171\,m.s^{-1}

b)H=8.9605\,m

Explanation:

Given:

mass of bullet, m=4.97\times 10^{-3}\,kg

compression of the spring, \Delta x=0.0476\,m

force required for the given compression, F=9.12 \,N

(a)

We know

F=m.a

where:

a= acceleration

9.12=4.97\times 10^{-3}\times a

a\approx 1835\,m.s^{-2}\\

we have:

initial velocity,u=0\,m.s^{-1}

Using the eq. of motion:

v^2=u^2+2a.\Delta x

where:

v= final velocity after the separation of spring with the bullet.

v^2= 0^2+2\times 1835\times 0.0476

v=13.2171\,m.s^{-1}

(b)

Now, in vertical direction we take the above velocity as the initial velocity "u"

so,

u=13.2171\,m.s^{-1}

∵At maximum height the final velocity will be zero

v=0\,m.s^{-1}

Using the equation of motion:

v^2=u^2-2g.h

where:

h= height

g= acceleration due to gravity

0^2=13.2171^2-2\times 9.8\times h

h=8.9129\,m

is the height from the release position of the spring.

So, the height from the latched position be:

H=h+\Delta x

H=8.9129+0.0476

H=8.9605\,m

4 0
3 years ago
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