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Rashid [163]
3 years ago
9

When a basketball player dribbles a ball, it falls to the floor and bounces up. Is a force required to make it bounce? Why? If a

force is needed, what is the agent involved?
Physics
1 answer:
Marizza181 [45]3 years ago
5 0
Energy is the one that is stored in the ball when it drops. Just before it hits the ground, the energy depends on the mass of the ball and its velocity. When the ball hits, it is compressed and the energy is stored in the compression of the air in the ball and the elasticity of the material that the ball is made from. Some is also converted to heat. The stored energy in the ball causes a force to make the ball back into a round shape and this force presses against the propels and floor the ball back up. The small amount lost as heat is the reason that the ball bounces up with less energy than when it hit.
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Match each coordinate used on a globe of earth to its counterpart on the celestial sphere
nika2105 [10]
I hope it will help u!!!!!!!
Equator------------------C::::::::::::::
Latitude------------------B::::::::::::::
Longitude---------------A::::::::::::::
3 0
4 years ago
A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0
3 years ago
Planets beyond the solar system.On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital dista
Evgesh-ka [11]

Answer:

Part a)

M = 2.31 \times 10^{30} kg

Part b)

M = 1.15 M_s

Explanation:

Part a)

As we know that the period of revolution of the planet is given by

T = 2\pi\sqrt{\frac{r^3}{GM}}

now we know that

r = 10.5 \times 10^6 km = 1.05 \times 10^{10} m

T = 6.3 days

T = 5.44 \times 10^5 s

now we have

5.44 \times 10^5 = 2\pi\sqrt{\frac{(1.05\times 10^{10})^3}{(6.67 \times 10^{-11})M}}

M = 2.31 \times 10^{30} kg

Part b)

As we know that mass of sun is given as

M_s = 2.0 \times 10^{30} kg

now we have

\frac{M}{M_s} = \frac{2.31 \times 10^{30}}{2 \times 10^{30}}

M = 1.15 M_s

6 0
4 years ago
Which term describes the relationship between wax and wane
andreyandreev [35.5K]
Those two words are antonyms ... two words with opposite meanings.
"Wax" means "grow".
"Wane" means "shrink".
3 0
4 years ago
g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin
Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

       i.e Normal \ Force(N)  = mg cos \theta

And \theta = 90 so

           N = 0

c

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position        

d

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work  

Explanation:

5 0
3 years ago
Read 2 more answers
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