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3 years ago

Siven an element's atomic number and mass number, how can you tell the number of protons and neutrons in its nucleus?

Physics

2 answers:

Ivahew [28]3 years ago

7 0

Answer:

Number of protons = atomic number; number of neutrons = mass number - atomic number

Explanation:

Z = atomic number = number of protons

A = mass number = number of protons + number of neutrons

Mass number = atomic number + number of neutrons

Number of neutrons = mass number - atomic number

sukhopar [10]3 years ago

3 0

It would be the first option.

Explanation-
The number of protons is equal to the atomic number the number of neutrons is the mass minus the atomic number.

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In your own words, describe the matter found in the universe and the relationship between stars, galaxies, and planets.

Darina [25.2K]

The universe is made up of baryonic matter which is a combination of protons, electrons, and neutrons, and also dark matter and dark energy.

Galaxies are comprised of stars, while the universe is comprised of galaxies.

I hope my answer has come to your help. God bless and have a nice day ahead!

6 0

4 years ago

Read 2 more answers

A model rocket is launched with an initial upward velocity of.

REY [17]

Answer:
A model rocket is launched with an initial upward velocity of 215 ft/s.

Explanation:

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2 years ago

Gwar [14]

Answer:

For 1: The correct option is Option C.

For 3: The final velocity of the opponent is 1m/s

Explanation:

During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$ ...(1)

where,

$m_1,u_1\text{ and }v_1$ are the mass, initial velocity and final velocity of first object

$m_2,u_2\text{ and }v_2$ are the mass, initial velocity and final velocity of second object

For 1:

We are Given:

$m_1=150g=0.15kg\\u_1=?m/s\\v_1=0.85m/s\\m_2=3500g=3.5kg\\u_2=0m/s\\v_2=0.85m/s$

Putting values in equation 1, we get:

$(0.15\times u_1)+(3.5\times 0)=(3.5+0.15)\times 0.85\\\\u_1=20.683\approx 21m/s$

Hence, the correct answer is Option C.

For 2:

Impulse is defined as the product of force applied on an object and time taken by the object.

Mathematically,

$J=F\times t$

where,

F = force applied on the object

t = time taken

J = impulse on that object

Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.

Hence, the impulse remains the same.

For 3:

Let the speed in right direction be positive and left direction be negative.

We are Given:

$m_1=240kg\\u_1=0m/s\\v_1=-1m/s\\m_2=80kg\\u_2=-2m/s\\v_2=?m/s$

Putting values in equation 1, we get:

$(240\times 0)+(80\times (-2))=(240\times (-1))+(80\times v_2)\\\\v_2=1m/s$

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.

4 0

3 years ago

Define escape velocity

lianna [129]

Answer:

the lowest velocity which a body must have in order to escape the gravitational attraction of a particular planet or other object.

Explanation:

8 0

3 years ago

Read 2 more answers

As a science fair project, you want to launch an 950 g model rocket straight up and hit a horizontally moving target as it passe

Aleksandr-060686 [28]

Answer:

As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?

= 43.56m

Explanation:

acceleration =

(20 - (0.95 * 9.8) )/ (0.95)

= 10.68 / 0.95

= 11.24 m/s²

we use

s = ut + (1/2) at²

Given that

s= 40

u =0

s = 0 * t + (1/2) (11.24)t²

t = √(66/1.24)

t = √5.87

t = 2.42sec

hence

Horizontal distance = 18 * 2.42

= 43.56m

5 0

3 years ago