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4 years ago

Which of the following changes the mass of an object?

Physics

2 answers:

Stolb23 [73]4 years ago

8 0

I think its either b. or d. i know its not a. It might be B. hope this helps?

Mamont248 [21]4 years ago

6 0

Answer:

A) Nothing, mass stays constant

Explanation:

As we know that mass is the measure of the quantity of the matter and it remains the same until we break or remove the part of the mass from its system.

So here we can say that

as the gravity change the value of the gravitational force will change as we know that

$F_g = mass \times gravity$

so we can say that

all the effects of height or distance from the center will change the gravity due to planet so it will not affect the mass of the system

so here correct answer would be

A) Nothing, mass stays constant

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The most abundant element in the universe is:

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Hydrogen and then its helium

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3 years ago

Which represents potential energy?

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C) is the correct answer.

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4 years ago

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The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center. If

zvonat [6]

Answer:

The distance between their eye and the ceiling is 33.06 m.

Explanation:

Given that,

The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm

Diameter of the eye of pupil, d = 5.1 mm

Wavelength, $\lambda=550\ nm$

We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :

$L=\dfrac{Dd}{1.22\lambda}\\\\L=\dfrac{4.35\times 10^{-3}\times 5.1\times 10^{-3}}{1.22\times 550\times 10^{-9}}\\\\L=33.06\ m$

So, the distance between their eye and the ceiling is 33.06 m.

3 0

3 years ago

A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw

Alona [7]

Answer:a

Explanation:

4 0

3 years ago

A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The

Goshia [24]

Answer:

$0.629\ \text{rad/s}^2$ counterclockwise

$9.98\ \text{s}$

Explanation:

$r_1$ = Small drive wheel radius = 2.2 cm

$\alpha_1$ = Angular acceleration of the small drive wheel = $8\ \text{rad/s}^2$

$r_2$ = Radius of pottery wheel = 28 cm

$\alpha_2$ = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

$r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2$

The angular acceleration of the pottery wheel is $0.629\ \text{rad/s}^2$ .

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

$\omega_i$ = Initial angular velocity = 0

$\omega_f$ = Final angular velocity = $60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}$

t = Time taken

From the kinematic equations of linear motion we have

$\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}$

The time it takes the pottery wheel to reach the required speed is $9.98\ \text{s}$

4 0

3 years ago