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pickupchik [31]
3 years ago
13

Gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 21

. g of ethane is mixed with 110. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 2 significant digits.
Chemistry
1 answer:
Anna11 [10]3 years ago
6 0

The chemical reaction for this is:

 

2 C2H6 + 7 O2 => 4 CO2 + 6 H2O

 

Solving for CO2 with each reactant will give:

 

21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2 mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O

 

110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x (18 g H2O/1 mol H2O) = 53.04 g H2O

 

Since the amount of H2O in C2H6 is lower therefore C2H6 is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)


ANswer:

38 g water

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2 years ago
Rasheed calculates that his chemical reaction should produce 4 moles of product, but when he does the experiment, he gets only 3
Brut [27]

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The answer to your question is 75%

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Acetylene gas (c2h2) reacts with oxygen gas (o2) to produce carbon dioxide (co2) and water vapor (h2o). how many liters of c2h2
MissTica
According to the balanced equation of the reaction:

2C2H2 + 5O2 → 4CO2 + 2H2O

So we can mention all as liters,

A) as we see that 2 liters of C2H2 react with 5 liters of oxygen to produce 4 liters of CO4 and 2 liters of H2O 

So, when we have 75L of CO2

and when we have 2 L of C2H2 reacts and gives 4 L of CO2

 2C2H2 → 4CO2 

∴ The volume of C2H2 required is:

                    = 75L / 2

                    = 37.5 L

B) and, when we have 75 L of CO2


and 4CO2 → 2H2O 

∴ the volume of H2O required is: 
                               
                            = 75 L /2
                            = 37.5 L 


C) and from the balanced equation and by  the same way:

when 5 liters O2  reacts to give 4 liters of CO2

and we have 75 L of CO2:

5 O2 → 4 CO2 

   ??  ←  75 L

∴ the volume of O2 required is:

                              = 75 *(5/4)

                              = 93.75 L



D) about the using of the number of moles the answer is: 

no, there is no need to find the number of moles as we called everything in the balanced equation by liters and use it as a liter unit to get the volume, without the need to get the number of moles.
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