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pickupchik [31]
3 years ago
13

Gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 21

. g of ethane is mixed with 110. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 2 significant digits.
Chemistry
1 answer:
Anna11 [10]3 years ago
6 0

The chemical reaction for this is:

 

2 C2H6 + 7 O2 => 4 CO2 + 6 H2O

 

Solving for CO2 with each reactant will give:

 

21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2 mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O

 

110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x (18 g H2O/1 mol H2O) = 53.04 g H2O

 

Since the amount of H2O in C2H6 is lower therefore C2H6 is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)


ANswer:

38 g water

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A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential (s)(aq)(aq)(l)
miv72 [106K]

Answer:

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)  

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

E°cell = 1.10 V

Explanation:

<em>The half-reactions are missing, but I will propose some to show you the general procedure and then you can apply it to your equations.</em>

<em>Suppose we have the following half-reactions.</em>

<em>Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V</em>

<em>Zn²⁺(⁺aq) + 2 e⁻ → Zn(s)    E°red = -0.76 V</em>

<em />

To identify how to make a spontaneous cell, we need to consider the standard reduction potentials (E°red). The half-reaction with the higher E°red will occur as a reduction (in the cathode), whereas the one with the lower E°red will occur as an oxidation (in the anode).

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        E°red = -0.76 V

To get the overall equation we add both half-reactions.

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

E°cell = 0.34 V - (-0.76 V) = 1.10 V

Since E°cell > 0, the reaction is spontaneous.

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2 years ago
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