Answer:
0.5 × 10²³ atoms of iodine
Explanation:
Given data:
Mass of calcium iodide = 12.75 g
Number of atoms of iodine = ?
Solution:
First of all we will calculate the number of moles of calcium iodide.
Number of moles = mass/ molar mass
Number of moles = 12.75 g/ 293.9 g/mol
Number of moles = 0.04 mol
In one mole of calcium iodide there are two moles of iodine.
Thus in 0.04 moles:
0.04 mol × 2 = 0.08 moles of iodine
Now we will use the Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
0.08 moles of iodine × 6.022 × 10²³ atoms / 1 mol
0.5 × 10²³ atoms of iodine.
Answer:
Explanation:
Trick question. The cathode is where the reduction reaction takes place. The reduction reaction is the gain of electrons.
Pb+2 + 2e^- ===> Pb The eo for that is - 0.126.
The minus sign indicates that the Pb^2+ is not overjoyed at taking on those two electrons. If it had a say in the matter, it would rather be giving up electrons. In other words, it would rather be the oxidizing equation which would look like this
Pb ===> Pb+2 + 2e^- and the oxidizing potential would be eo = + 0.126
That's what moving right and moving left means. If the eo is - then the preferred reaction is the opposite one.
This is a real language problem and if Znk answers you can take his answer to the bank.
The balanced chemical reaction is expressed as:
<span>C3H8 + 5 O2 -> 3 CO2 + 4 H2O
We are given the amount of water produced. We use this amount for the calculations. We do as follows:
16.3 mol H2O ( 1 mol C3H8 / 4 mol H2O ) = 4.075 mol C3H8 needed
Hope this answers the question. Have a nice day.</span>
Answer:
False.
Explanation:
(5 kilometers / 30 minutes), you could then say that in 60 minutes (one hour) you would be traveling at (10 kilometers / 60 minutes)...
Therefore, it is unlikely that you would be traveling at (6 kilometers / hour), so the answer should be... False.
