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3 years ago

Please someone help me Balance this equation.

Chemistry

1 answer:

NeTakaya3 years ago

7 0

Answer: This is an oxidation-reduction (redox) reaction:

3 C-II - 12 e- → 3 CII (oxidation)

4 CrVI + 12 e- → 4 CrIII (reduction)

C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.

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PLS HELP

alexandr1967 [171]

Answer:

Explanation:

A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1

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3 years ago

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A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight

melomori [17]

Given:

volume of 0.08 m³

density of 7,840 kg/m³

Required:

force of gravity

Solution:

Find the mass using density equation.

D = M/V

M = DV

M = (7,840 kg/m³)(0.08 m³)

M = 627.2kg

F = Mg

F = (627.2kg)(9.8m/s2)

F = 6147N

7 0

3 years ago

Catalyst

Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

$\tt \dfrac{4}{5}\times 0.5=0.4$

volume NO at 1273 K and 1 atm

$\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L$

b. 15 L NH3 at STP ( 1mol = 22.4 L)

$\tt \dfrac{15}{22.4}=0.67~mol$

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

$\tt \dfrac{6}{4}\times 0.67=1$

mass H2O(MW = 18 g/mol) :

$\tt mass=mol\times MW=1\times 18=18~g$

c. mol NO at 1273 K and 1 atm :

$\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34$

mol ratio of NO : O2 = 4 : 5, so mol O2 :

$\tt \dfrac{5}{4}\times 0.34=0.425$

Volume O2 at STP :

$\tt 0.425\times 22.4=9.52~L$

5 0

3 years ago

An organism that makes or creates their own food?

Sedaia [141]

I think producer

option is A

5 0

3 years ago

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A compound with the formula C6H14 was reacted with Cl2/light to give a mixture of 5 different monochlorinated products (not incl

allochka39001 [22]

Answer:

Hexane.

Explanation:

Hello!

In this case, since the general reaction of the compound C4H14 with chlorine is:

$C_6H_{14}+Cl_2\rightarrow C_6H_{13}Cl+HCl$

Which stands for a substitution chemical reaction in which one chlorine is able to replace one hydrogen and therefore hydrogen chloride gives off; we infer that the initial compound, C4H14, shows off the $C_nH_{2n+2}$ formula characteristic of alkanes; in such a way, as it has six carbon atoms, we infer it is hexane.

Best regards!

6 0

3 years ago