9514 1404 393
Answer:
B. Figure B
Step-by-step explanation:
The figure is difficult to read. We assume the height of the pyramid is 9, and the radius of the cylinder is 1.
The pyramid volume is ...
V = 1/3Bh
V = 1/3(4²)(9) = 48 . . . cubic units
__
The cylinder volume is ...
V = πr²h
V = π(1²)(48) = 48π . . . cubic units
The cylinder has π times as much volume as the pyramid. Figure B is larger.
_____
<em>Additional comment</em>
If the diameter (not the radius) of the cylinder is 1 unit, then its volume is 12π cubic units and the pyramid has more volume.
<span>going downstream -
t = 14/(2 + v)
going upstream -
t = 7/(2 - v)
14/(2 + v) = 7/(2 - v)
(2 + v)/2 = 2 - v
v = 2/3km/h</span><span>
</span>
Answer:
the answer is D 8.8
Step-by-step explanation:
17x>102
Divide both sides by 17:
x>6
To solve this problem you must keep on min the information given in the problem shown above:
1- You have that
<span>
- The height reached by amal's rocket was 1/4 of the height reached by min's rocket.
- Amal's rocket REAched a height of 15 meters.
</span>
2. Therefore, let's call "x" to the <span>height reached by min's rocket. Then, you have:
</span>
(1/4)x=15
x/4=15
<span> Which equation could be used to find the height reached by min's rocket?
</span>
The answer is: x/4=15
