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abruzzese [7]
3 years ago
10

the expenses of a tea party are partly constant and partly vary directly with the number of guest.when there are 60 guest,the ex

penses are $2100.when there are 150 guest , the expenses are $4800.find the expenses when there are 200 guest​
Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

$6300

Step-by-step explanation:

Using the equation of y=mx+c where c is constant, m is gradient then the two situations can be written as

2100=60x+c Equation 1

4800=150x+c Equation 2

Subtracting the terms of equation 1 from 2

(150-60)x=$4800-$2100

90x=$2700

x=$30

Substituting the value x into equation 1

60($30)+c=$2100

c=$2100-$1800=$300

c=$300

For 200 guests

y=200($30)+$300

y=$6000+$300=$6300

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The number of candies that will be <u>left over</u> after giving everyone an equal amount is equal to 23.

<u>Given the following data:</u>

  • Total number of candy = 320 pieces
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To calculate the number of candies that will be <u>left over</u> after giving everyone an equal amount:

In this exercise, you're required to determine the number of candies Phillipe would have as <u>left over</u> after giving everyone in his class an equal amount of candies.

<h3>How to solve this word problem.</h3>

Thus, we would find the number of times 27 would divide 320 without any remainder.

\frac{320}{27} = 11 \frac{23}{27}

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Therefore, the number of candies that will be <u>left over</u> after giving everyone an equal amount is equal to 23.

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2 years ago
The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon
Stells [14]

Answer:

(a)D(q)=\frac{-1}{25} q+148

(b)S(q)=\frac{1}{50}q+58

(c)p_{*} =88\\\\q_{*} =1500

Step-by-step explanation:

(a) For the demand equation D(q) we have

<em>P1: 138 Q1: 250</em>

<em>P2: 108 Q2: 1000</em>

We can find <u><em>m</em></u>, which is the slope of the demand equation,

m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148

<em>With b: 148 and m: -1/25 we can write our demand equation D(q)</em>

D(q)=\frac{-1}{25} q+148

(b) to find the supply equation S(q) we have

<em>P1: 102 Q1: 2200</em>

<em>P2: 102 Q2: 700</em>

<em></em>

Similarly we find <em>m</em>, and <em>b</em>

m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}

y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\

<em>And we can write our Supply equation S(q):</em>

S(q)=\frac{1}{50}q+58

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing <em>D(q)=S(q)</em>, which means the demand <u><em>equals</em></u> the supply in equilibrium:

D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\

148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\

We plug 1500 as q into any equation, in this case S(q) and we get:

S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88

Which is the equilibrium price p*.

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Step-by-step explanation:

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