The other quantity which might be of interest is initial velocity
<h3>What is maximum height?</h3>
The maximum height of the object can be defined as the highest vertical position along its trajectory line.
The range of the projectile is also known as the horizontal displacement of the projectile. It is largely dependent on the initial velocity of the object.
If;
- v is the initial velocity
- g = acceleration due to gravity
- H = maximum height in meters
- θ = angle of the initial velocity from the horizontal plane (radians or degrees).
Maximum height of projectile is given by the formula:
From this, we can deduce that another quantity of interest is initial velocity
Thus, the other quantity which might be of interest is initial velocity
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3m-9=9+3m
add 9 to both sides
3m=18+3m
minus 3m both sides
0=18
false
no solution
the best discription would be an empty solution set
Answer:
Step-by-step explanation:
The average speed in function of the temperature:
The distance in function of the average speed:
x and S are the same
![D(t)=0.5*[6 \frac{miles}{hour} +0.1*\frac{miles}{hour*F}(80F-t)]](https://tex.z-dn.net/?f=D%28t%29%3D0.5%2A%5B6%20%5Cfrac%7Bmiles%7D%7Bhour%7D%20%2B0.1%2A%5Cfrac%7Bmiles%7D%7Bhour%2AF%7D%2880F-t%29%5D)
Answer:
It's D
Step-by-step explanation:
Volume of a Right circular cylinder=πr²h
Using "Cavaliers principle" or Just pire logic... it can be understood that...
if we were to cut of the base and top of the cylinder such that it will make up to be a right circular cylinder and join the other two pieces on top; We would obtain a Right circular cylinder With The same radius and height as the Given cylinder.
So;
Given. Base area B=81πcm²
also Base area =πr²
=>πr²=81π cm²
=>r=√81=9cm
Also Given;
Height h=3r
=>Height,h=3×9=27cm
So;Volume of cylinder V=πr²h ;(r²=81,h=27)
=>V=(81×27×22)/7
=>V=6867.18cm³ (approx.)
So,Required Volume =6867.18cm³(approx.)
Hope it helps...
Regards,
Leukonov/Olegion.
