Answer:
2g^2 +8g +30 + 112/(g-4)
Step-by-step explanation:
2g^3 + 0g^2 -2g -8 divide by g-4
The coefficients go on the first line and the root goes in the divisor spot
Bring down the first coefficient
2 0 -2 -8
4
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2
Multiply the root by the number on the bottom and add to the coefficient
2 0 -2 -8
4 8
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2 8
Multiply the root by the number on the bottom and add to the coefficient
2 0 -2 -8
4 8 32
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2 8 30
Multiply the root by the number on the bottom and add to the coefficient
2 0 -2 -8
4 8 32 120
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2 8 30 112
Since this was a third degree polynomial, we subtract 1 from the power and we have a second degree polynomial as our answer. The first term is the coefficient of the 2nd degree term and so on until we get to the last term which is the remainder. We put that over the divisor.
2g^2 +8g +30 + 112/(g-4)