A cable that connects the computer to the printer is an example of A.hardware B.software

a.) Software architecture is the set of principal design decisions about a system. b.) Software architecture dictates the proces

Shtirlitz [24]

Question:

Which of the following statements is not a true statement about software architecture?

Answer:

b.) Software architecture dictates the process used by a team to develop use cases for a software system.

Explanation:

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications. There are six (6) main stages in the creation of a software and these are;

1. Planning.

2. Analysis.

3. Design.

4. Development (coding).

5. Deployment.

6. Maintenance.

One of the most important steps in the software development life cycle (SDLC) is design. It is the third step of SDLC and comes immediately after the analysis stage.

Basically, method design is the stage where the software developer describes the features, architecture and functions of the proposed solution in accordance with a standard.

Software architecture can be defined as the software blueprint or infrastructure in which the components (elements) of the software providing user functionality and their relationships are defined, deployed and executed. Thus, it is a structured framework used by software developers to model software components (elements), properties and relationships in order to have a good understanding of how the program would behave.

In conclusion, software architecture doesn't dictate the process used by a team to develop use cases for a software system.

6 0

3 years ago

Python - Please help!

Margaret [11]

Answer:

i= 1

for i in range(1,n):

if i * i < n:

print(2* i + 1)

i += 1

else:

print('Hakuna Matata')

Explanation:

First, there's a need to rewrite the code segment in your question (because of indentation)

i= 1

while i*i < n:

print(2* i + 1)

i += 1

else:

print('Hakuna Matata')

The explanation of the equivalent of the above while loop is as follows

This line initializes i to 1

i= 1

This line iterates from 1 to n-1

for i in range(1,n):

This line checks if i * i is less than n

if i * i < n:

The following line is executed if the above condition is satisfied; otherwise, nothing is done

print(2* i + 1)

The value of i is incremented by 1 using this line

i += 1

The following is executed at the end of the iteration

else:

print('Hakuna Matata')

Note: Assume any value of n, both programs display the same output

6 0

3 years ago

[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri

AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name -> Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 ( Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name -> Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 ( Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ). with candidate keys Course_Name and Course_ID.

6 0

4 years ago

What is the output of the code below? PLEASE HELP!! TIME LIMIT!!

Vladimir [108]

Answer:

bc

Explanation:

5 0

3 years ago

How does a spreadsheet affect the column of numerals when it sorts the column

Setler [38]

You have several options when you want to enter data manually in excel. Data can be put into more than one cell, which should be an important key to your answer. In SEVERAL CELLS AT THE SAME TIME or more. The data can be entered in dates, text, times, or numbers. Fortmatting the data can be done in a possibility of ways. Therefore, several settings is what you can adjust.

6 0

3 years ago

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