Answer:
Explanation:
2 NO2(g) ⇄ N2O4(g)
Adding Argon to this reaction will have NO effect. Catalysts nor inert gases have an affect on equilibrium conditions.
Only changes in concentration, temperature conditions and pressure-volume conditions (unless both sides have equal molar volumes) will affect the equilibria.
NH4OH(aq) ⇄ NH3(g) + H2O(l)
Removing ammonia from reaction equilibrium causes the reaction to shift right to replace removed ammonia. => Think of the reaction as being on a seesaw => removing ammonia from the product side tilts the seesaw left causing the NH₄OH to decompose and deliver more NH₃ and H₂O to the product side to increase weight on that side and level the seesaw. :-)
Controlled variables: do not change as they must be held constant
Independent variables: are controlled and manipulated
Dependent variables: effected by changes to the independent variable
Answer:
91.5 mol
Explanation:
Volume of gas = 70 L
Temperature = 25°C
Pressure = 32 atm
Moles of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273.15 = 298.15 K
By putting values,
32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K
2240 atm.L = n ×24.48 atm.L /mol
n = 2240 atm.L / 24.48 atm.L /mol
n = 91.5 mol
F<span>luorine
F</span><span>luorine is considered the most electronegative element.</span>