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dybincka [34]
3 years ago
13

Juan observes a material in the rocks of a hilluan hammers off a piece and then examines the pieces with a hana tena He

Chemistry
1 answer:
Nata [24]3 years ago
5 0

Answer:

I definitely think he mostly observed that it was clear in color.

Explanation:

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Someone pls help me I will make you brain
sertanlavr [38]

Answer:

I believe the answer is II and III

Explanation:

I'm not sure if III is right cause I cannot read the last word but I think it's OK.

Hope this helped :)

4 0
3 years ago
General size of a nebula
Salsk061 [2.6K]
Can range anywhere from 1 AU to 10 AU
4 0
3 years ago
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The image shows particles of salt dissolved in water.
user100 [1]

Answer: Hope it may help you

Explanation:

Diffusion can be defined as the movement of particles from a region where there a more concentration of solute to the region having less concentration of the solute.

Here, the salt particles will move from right side of the box to the left side of the box.

This is because the right side has more particle and the left side has less particles so they will move towards the left side.

6 0
3 years ago
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Calculate q (in units of joules) when 1.850 g of water is heated from 22 °C to 33 °C. Report only the numerical portion of your
Minchanka [31]
When q is the heat energy in joules (J)

so, according to this formula, we can get q (in joule unit):

q = M*C*ΔT

when M is the mass of the water sample = 1.85 g

C is the specific heat capacity of water = 4.18 J/g.°C

and Δ T is the difference in temperature (Tf-Ti) = 33 - 22 = 11°C

So, by substitution, we will get the value of q ( in Joule):

∴ q = 1.85 g * 4.18 J/g.°C * 11 °C

      = 85 J
5 0
3 years ago
you are holding a bowling ball with a mass of 6 kg at a height of 1 meter. How much gravitational potential energy does the bowl
Bumek [7]

The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,

PE=mgh

PE=(6 kg)(9.8 m/s^2)(1 m)

PE=58.8 kg•m^2/s^2 or 58.8 Newtons

The GPE of the bowling ball under these conditions would be about 59 Newtons.

Hope this helps!

7 0
4 years ago
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