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Irina18 [472]
2 years ago
11

Find compound interest on12600rupees for 2years at10% per annum compounded anually​

Mathematics
1 answer:
vekshin12 years ago
3 0

Answer:

₹2520

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 10%/100 = 0.1 per year,

then, solving our equation

I = 12600 × 0.1 × 2 = 2520

I = ₹ 2,520.00

The simple interest accumulated

on a principal of ₹ 12,600.00

at a rate of 10% per year

for 2 years is ₹ 2,520.00.

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3 years ago
Reduce -8 + b2 by 5 + b2.<br><br> -3<br> 2b² - 3<br> -13
Eddi Din [679]
-8+b2-(5+b2). Since the - is outside the paranthesis the signs inside change: -8+b2-5-b2. -8-5=-3, b2-b2=0. Your answer: -3 :)
5 0
3 years ago
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What is are if a rectangle of length of 5 and width of 3x-5y+6What is the area of a rectangle with a length of 5 and a width of
lawyer [7]

The area of rectangle is 15x - 25y + 30 sqaure units

<em><u>Solution:</u></em>

Given that, a rectangle with a length of 5 and a width of 3x - 5y + 6

To find: Area of rectangle

<em><u>The area of rectangle is given by formula:</u></em>

Area = length \times width

From given,

Length = 5

Width = 3x - 5y + 6

<em><u>Substituting the values in formula, we get,</u></em>

Area = 5 \times (3x - 5y + 6)\\\\\text{Multiply 5 with each term inside the bracket }\\\\Area = 5(3x) -(5)(5y) +5(6)\\\\\text{Simplify the above expression }\\\\Area = 15x -25y + 30

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6 0
3 years ago
2. An articulated truck is loaded with cylindrical containers filled with oil. The height of each container is 80cm and the diam
RoseWind [281]

The volume of each container is: 25,133 cm^{3}

Given:

height of container (h) = 80 cm

diameter of container (d) = 20 cm

radius = half of diameter = \frac{1}{2} of 20 = 10 cm

Recall:

Volume of a cylinder = \pi r^{2} h

<em>Substitute the values into the formula:</em>

Volume = \pi \times 10^{2} \times 80 = 25132.74123

Therefore, volume of each cylinder is approximately 25,133 cm^{3}

Learn more about volume of cylinder here:

brainly.com/question/971817

8 0
3 years ago
Given that ABCD congruent to PQRS, solve for m<br><br><br> A.0.5<br> B.2.5<br> C.3<br> D.5
34kurt
As the 2 quadrilaterals are congruent the sides of one quadrilateral are equal to the corresponding sides of the other quadrilateral
Hence,
AB = PQ
RQ = BC
AD = PS
DC = RS
Since terms for both AB and PQ are given we can equate the terms and find m
5m -9 = m + 11
5m -m = 11 + 9
4m = 20
m = 5
Correct answer is D , 5
3 0
3 years ago
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