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3 years ago

Finding the product

Mathematics

1 answer:

pshichka [43]3 years ago

6 0

Use a box. Split the terms into the boxes and then multiply across. Sort of like area multiplication, only with terms.

3 5x
4y 12y 20xy

3 9 15x

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Slove for x: x+1/3=1/4

lana [24]

Hey!

To solve this problem, we must subtract one over three from both sides of the equation. This will give us x on its own.

Original Equation :
$x + \frac{1}{3} = \frac{1}{4}$

New Equation {Added Subtract $\frac{1}{3}$ to Both Sides} :
$x + \frac{1}{3} - \frac{1}{3} = \frac{1}{4} - \frac{1}{3}$

Solution {New Equation Solved} :
$x=- \frac{1}{12}$

So, this means that in the equation provided, $x=- \frac{1}{12}$ .

Hope this helps!

- Lindsey Frazier ♥

6 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago

A group of students were surveyed to find out if they like building snowmen or skiing as a winter activity. The results of the s

soldier1979 [14.2K]

Building Snowmen - 60
Building Snowmen (no skiing) - 10
Skiing - 80
No to building snowmen - 50

Part A:
total of students: 200
140 x
----- = ----
200 100
14000 200x
--------- = --------
200 200
70 = x
70%

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3 years ago

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What are the 3 other terms that are the same as the solutions of a quadratic equation

expeople1 [14]

Roots zeros and x values

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3 years ago

I need help with this pls

Vilka [71]

Each chore he completed he gets $3

so 5 x 3 = 15

answer is 15

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4 years ago

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