Question

An architect maps two buildings, which are located on a piece of land, onto a coordinate plane. He wants to build a wall at the diagonal AC to divide the piece of land into two parts. What will be the length of the wall? A. 65–√ units B. 6 units C. 237−−√ units D. 2 units

Answer 1

Answer:

$6\sqrt{5} units$

Step-by-step Explanation:

The length of the wall = diagonal AC = distance between point A (-6, -2) and point C (6, 4).

Distance formula between two points on a graph (d) = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Where,

$A(-6, -2) = (x_1, y_1)$

$C(6, 4) = (x_2, y_2)$

$d = \sqrt{(6 - (-6))^2 + (4 -(-2))^2}$

$d = \sqrt{(6 + 6)^2 + (4 + 2)^2}$

$d = \sqrt{(12)^2 + (6)^2}$

$d = \sqrt{144 + 36}$

$d = \sqrt{180}$

$d = \sqrt{36*5}$

$d = 6\sqrt{5}$

The length of the wall = $6\sqrt{5} units$

Answer 2

Answer:

6$6\5sqrt{x}$

Step-by-step explanation: