1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Cloud [144]
3 years ago
8

What type of bond is formed between sodium and iodine in sodium iodide (NaI)? A. ionic B. metallic C. polar covalent D. nonpolar

covalent
Chemistry
1 answer:
iragen [17]3 years ago
7 0

Answer: Option (A) is the correct answer.

Explanation:

When two atoms share electrons then it results in the formation of covalent bond. Whereas when there is transfer of electrons between two atoms then it forms an ionic bond.

Sodium is a metal so it has excess of electrons whereas iodine is a non-metal so it is electron deficient.

So, sodium will give its extra electron to iodine thus due to transfer of electron it results in the formation of ionic bond.

You might be interested in
The temperature of a substance is a measure of its particles in
Fantom [35]
Brownian(Chaotic) motion
3 0
4 years ago
Calcium carbonate+nitic acid
miss Akunina [59]

Answer:

What does calcium carbonate and nitric acid make?

Explanation:

Calcium carbonate reacts with nitric acid to produce carbon dioxide.

is this what you wanted to know?

8 0
3 years ago
Consider the equilibrium
vladimir1956 [14]

Answer:

Kp^{1000K}=0.141\\Kp^{298.15K}=2.01x10^{-18}

\Delta _rG=1.01x10^5J/mol

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

C_2H_6(g)\rightleftharpoons H_2(g)+C_2H_4(g)

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:

p_{C_2H_6}^{EQ}=2bar*0.592=1.184bar\\p_{C_2H_4}^{EQ}=2bar*0.204=0.408bar\\p_{H_2}^{EQ}=2bar*0.204=0.408bar

Kp=\frac{p_{C_2H_4}^{EQ}p_{H_2}^{EQ}}{p_{C_2H_6}^{EQ}}=\frac{(0.408)(0.408)}{1.184}=0.141

Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

Ln(Kp^{298.15K})=Ln(Kp^{1000K})-\frac{\Delta _rH}{R}*(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=Ln(0.141)-\frac{137000J/mol}{8.314J/mol*K} *(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=-40.749\\\\Kp^{298.15K}=exp(-40.749)=2.01x10^{-18}

Finally, the Gibbs free energy for the reaction at 298.15K is:

\Delta _rG=-RTln(Kp^{298.15K})=8.314J/mol*K*298.15K*ln(2.01x10^{-18})\\\Delta _rG=1.01x10^5J/mol

Best regards.

3 0
4 years ago
Please help!!
gregori [183]

Answer:

6.02 * 10^23 atoms

Explanation:

Avogadro's number

4 0
4 years ago
Two objects of equal mass have a force of gravity of 6 N between them. Imagine the mass of one is cut in half and the other stay
Alenkasestr [34]

Answer:

F' = 3 N

Explanation:

Given that,

Two objects of equal mass have a force of gravity of 6 N between them.

If the mass of one is cut in half and the other stays the same such that,

m₁' = m₁ and m₂' = (m₂/2)

We need to find the new force. The gravitational force between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}

We have, F = 6 N

New force,

F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N

So, the new force becomes 3 N.

3 0
3 years ago
Other questions:
  • ⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜​
    11·2 answers
  • How many unpaired electrons are present in the ground state of an atom from each of the following groups?
    6·1 answer
  • What is the difference between two atoms of carbon having the same number of neutrons?
    11·1 answer
  • Which products were produced or raised in large amounts on the prairie?
    9·2 answers
  • How many grams of 2.5% "h" cream should be mixed with360 grams of 0.25% "h" cream to make a 1% "h" cream?
    15·1 answer
  • For the reaction 2 H 2 O ( g ) − ⇀ ↽ − 2 H 2 ( g ) + O 2 ( g ) the equilibrium concentrations were found to be [ H 2 O ] = 0.250
    13·1 answer
  • La molaridad (m) de una disolucion que contiene 34,2 g de azucar, disueltos en 0,250 de agua
    6·1 answer
  • Why do astronauts on the moon seem like they're "Walking on springs" while on earth we are firmly attached to the ground
    13·2 answers
  • A solution is classified as a weak base. Which of these could be the pH of the solution?
    15·1 answer
  • What is the temperature change of an 36-gram sample of water that had absorbed 695 Joules of heat? C = 4.18 J/g K
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!