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Margaret [11]
3 years ago
12

Determine the net iconic equation for the following chemical reaction: HCl(aq) + NH4OH(aq)———-> NH4Cl(aq) + H2O(I) Hint: HCl(

aq) is strong acid NH4OH(aq) is a weak base
Chemistry
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer : The net ionic equation will be,

H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

HCl(aq)+NH_4OH(aq)\rightarrow NH_4Cl(aq)+H_2O(l)

The ionic equation in separated aqueous solution will be,

H^+(aq)+Cl^-(aq)+NH_4^+(aq)+OH^-(aq)\rightarrow H_2O(l)+NH_4^+(aq)+Cl^-(aq)

In this equation, NH_4^+\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)

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Number of molecules of oxygen produced along with one molecule of sugar
Brums [2.3K]

Answer:

6 molecules of Oxygen

Explanation:

From the question ,

Sugar has a molecular formula of C₆H₁₂O₆ .

Hence ,  

Using the mole concept , i.e. ,  

1 molecule of Sugar , i.e. , C₆H₁₂O₆ has , 6 molecules of Carbon , 12 molecules of Hydrogen and 6 molecules of Oxygen .  

Therefore ,  

6 molecules of Oxygen is present in 1 molecule of sugar , i.e. ,  C₆H₁₂O₆ .

5 0
3 years ago
An irregular lump of an unknown metal has a measured density of 5.50 g/mL. The metal is heated to a temperature of 153 °C and pl
Oliga [24]

Answer: 0.543J/g^0C

Explanation:

Volume of metal = volume of water displaced = (30.0 - 25.0) ml = 5.0 ml

Density of metal = 5.50 g/ml

Mass of metal =density\times volume =5.50\times 5.0=27.5g

Volume of water = 25.0 ml

Density of metal = 1.0 g/ml

Mass of metal =density\times volume =1.0\times 25.0=25.0g

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 27.5 g

m_2 = mass of water = 25.0 g

T_{final} = final temperature = ?41.0^0C

T_1 = temperature of metal = 153^oC

T_2 = temperature of water = 25.0^oC

c_1 = specific heat of lead = ?

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

27.5g\times c_1\times (41.0-153)^0C=[25.0g\times 4.814J/g^0C\times (41.0-25.0)^0C]

c_1=0.543J/g^0C

Thus the specific heat of the unknown metal sample is 0.543J/g^0C

7 0
3 years ago
What happens to the velocity of an object when balanced forces act on it?
Phantasy [73]

Answer:

There will be negative acceleration.

Explanation:

I majored in Physics

6 0
2 years ago
The two naturally occurring isotopes of antimony, 121Sb (57.21 percent) and 123Sb (42.79 percent), have masses of 120.904 and 12
Alex

Answer:

The correct answer is option c.

Explanation:

Formula used to determine an average atomic mass :

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

Mass of isotope Sb-121 = 120.904 amu

Fractional abundance of Sb-121 = 57.21% = 0.5721

Mass of isotope Sb-123 = 122.904 amu

Fractional abundance of Sb-123 = 42.79% = 0.4279

Average atomic mass of Sb:

120.904 amu\times 0.5721+ 122.904 amu\times 0.4279=121.7598 amu \approx 121.76 amu

7 0
3 years ago
How many moles of Boron (B) are in 5.03 x 1024 B atoms?
goldfiish [28.3K]

Hey there!:

Number of moles =   ( number of atoms / 6.023*10²³ atoms )

given number of atoms = 5.03*10²⁴

Therefore:

Number of moles B = 5.03*10²⁴ / 6.023*10²³

Number of moles B = 8.35 moles

Hope that helps!


3 0
3 years ago
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