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kotegsom [21]
3 years ago
10

In some areas of the Earth, the crust is squeezed and pushed upward. This is a _______ process in that it directly forms _______

.
Chemistry
2 answers:
NemiM [27]3 years ago
7 0
So..... I believe this is a Convergent boundary and mountains..
lyudmila [28]3 years ago
4 0

if you come from study island then the answer is constructive,mounatins

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4 years ago
Intermolecular Forces and Physical Properties of Pure Substances
sergiy2304 [10]

Answer: b

Explanation: because b is the right one i just did it.

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3 years ago
How many molecules of As4010 are in 6.2 mol of As4010?
notsponge [240]

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8 0
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Read 2 more answers
If 420 joules of heat energy is added to 25 grams of water at 25 degrees celcius, what will be the final temperature of the wate
natka813 [3]

Answer:

T2 = 29°C

Explanation:

Given data:

Heat added = 420 j

Mass of water = 25 g

Initial temperature = 25°C

Final temperature = ?

Solution;

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water = 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values.

420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)

420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)

420 j = 104.5  j/°C × (T2 - 25°C)

420 j /104.5  j/°C = T2 - 25°C

4°C + 25°C = T2

T2 = 29°C

4 0
3 years ago
Una masa de aire ocupa un volumen de5litro a una temperatura de 120c Cual será el nuevo volumen si la temperatura se reduce ala
zalisa [80]

Answer:

1. V_2=2.5L

2. V_2=8000mL

3. V_2=176.3L

Explanation:

¡Hola!

En este caso, dada la información para estos problemas, procedemos de la siguiente manera, basado en las leyes de los gases ideales:

1. Una masa de aire ocupa un volumen de 5 litros a una temperatura de 120 °C Cual será el nuevo volumen si la temperatura se reduce a la mitad:

Aqui, utilizamos la ley de Charles, asegurándonos que la temperatura está en Kelvin:

\frac{T_2}{V_2} =\frac{T_1}{V_1} \\\\V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{5L*196.5K}{393K} \\\\V_2=2.5L

2. Un gas ideal ocupa un volumen de 4000 ml a una presión absoluta de 1500 kilo pascal Cual será la presión si el gas es comprimido lentamente hasta 750 kilo pascal a temperatura constante?

Aquí, utilizamos la ley de Boyle, dado que la temperatura se mantiene constante, calculando el volumen, ya que lo que se da es la presión final:

\neq P_2V_2=P_1V_1\\\\V_2=\frac{P_1V_1}{P_2}\\\\ V_2=\frac{4000mL*1500kPa}{750kPa}\\\\V_2=8000mL

3. Un gas ocupa un volumen de 200 litros a 95°C y 782 mmHg Cual será el volumen ocupado por dicho gas a 65°C y 815 mmHg:

Aquí, utilizamos la ley combinada de los gases ideales, asegurándonos que las temperaturas están en Kelvin:

\frac{T_2}{P_2V_2} =\frac{T_1}{P_1V_1} \\\\V_2 =\frac{P_1V_1T_2}{P_2T_1} \\\\V_2 =\frac{782mmHg*200L*338K}{815mmHg*368K}\\\\V_2=176.3L

¡Saludos!

6 0
3 years ago
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