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Soloha48 [4]
3 years ago
10

In the Polyacrylamide and Agarose Gels lab, when working with your protein or DNA sample you must wear:

Chemistry
2 answers:
Phantasy [73]3 years ago
7 0
It’s a.all of these your welcome
blagie [28]3 years ago
6 0
It’s a. All of these, you’re welcome
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Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.
UNO [17]

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

4 0
3 years ago
Which of the following best describes a single replacement reaction?
Lady_Fox [76]

Answer:

One element takes the place of another in a compound

Explanation:

I just took a test for it and got it right. :)

Hope This Helps :)

6 0
2 years ago
What two methods are used for determining the age of rocks and fossils?
Alexandra [31]

Explanation:

first one because absolute dating is a thing for rock layers

7 0
3 years ago
Quick question
IceJOKER [234]

Answer:Um... I think 5000 i am not really sure

Explanation: I Dont Really Know

4 0
3 years ago
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
3 years ago
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