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gizmo_the_mogwai [7]
3 years ago
11

what is the slope of a line that is perpendicular to the line that contains points (5,4) and (-7,9). explain please

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

\frac{12}{5}

Step-by-step explanation:

First find the slope of the line containing points (5,4) and (-7,9).  To find the slope use the formula \frac{y_{2} -y_{1}}{x_{2}-x_{1}}.  Putting those values in, you have

\frac{9-4}{-7-5}

Simplify

\frac{5}{-12}

-\frac{5}{12}

Then, to find the slope of the line perpendicular to that, find the negative reciprocal.  

\frac{12}{5}

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If the x^2 coefficient is 1, i.e. the equation is written like x^2+bx+c=0, then you can say the following about the coefficients b and c:

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So, for example, if we want an equation whose roots are 4 and -2, we have:

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