The answer to the equation is
2x+11
i hope this helped :)
Answer: 14 days
Step-by-step explanation:
Day 1: 1 minute snooze = 24 minutes
Day 2: 2 minute nooze = 23 minutes ; these examples show snooze time = days.
We can set up an equation for this situation: 25 - s = r ; where s = snooze time and r = time to get ready.
Given the problem, we can fill out this equation with: 25 - s = 11
When you solve this equation, time snoozed = 14.
We already know that snooze time = days, so days = 14.
I am not a professional, simply using prior knowledge!
Note- It would mean the world to me if you could mark me brainliest!
1. -1/20
work: Write all numerators above the least common denominator: -8+2+5/20
*Calculate the sum or difference: -1/20
Answer:
-4/7, -1/3, -0.1, 0, 0.1
Step-by-step explanation:
Answer:
∫▒〖arctan(x).1 dx=arctan(x).x〗-1/2 ln(1+x^2 )+C
Step-by-step explanation:
∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗
Let 1st=arctan(x)
And 2nd=1
∫▒〖arctan(x).1 dx=arctan(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗
As we know that
derivative of arctan(x)=1/(1+x^2 )
∫▒〖1 dx〗=x
So
∫▒〖arctan(x).1 dx=arctan(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1
Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now
Let 1+x^2=u
du=2xdx
Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get
1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)
1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)
1/2 ∫▒(2xdx/u) =1/2 ln(u)+C
1/2 ∫▒(2xdx/u) =1/2 ln(1+x^2 )+C
Putting values in Eq1 we get
∫▒〖arctan(x).1 dx=arctan(x).x〗-1/2 ln(1+x^2 )+C (required soultion)
