Answer:
The volume of pyramid B is 81 cubic units
Step-by-step explanation:
Given
<u>Pyramid A</u>
-- base sides
-- Volume
<u>Pyramid B</u>
--- base sides
Required
Determine the volume of pyramid B <em>[Missing from the question]</em>
From the question, we understand that both pyramids are equilateral triangular pyramids.
The volume is calculated as:

Where B represents the area of the base equilateral triangle, and it is calculated as:

Where s represents the side lengths
First, we calculate the height of pyramid A
For Pyramid A, the base area is:




The height is calculated from:

This gives:

Make h the subject



To calculate the volume of pyramid B, we make use of:

Since the heights of both pyramids are the same, we can make use of:

The base area B, is then calculated as:

Where

So:



So:

Where
and 


