You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1
Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
Your 2nd option is the correct answer because 7 goes into both.
Answer:
use elimination
8x-3y=2
-8x-5y=46
8x cancel out
-5y-3y= -8y= 48
48/-8= -6y
Step-by-step explanation:
ANSWER= -6y
