Sine wave with amplitude 0.25
Period is 4/3
h(t) = 0.25Sin((2Pi/4/3)t) = 0.25Sin((3Pi/2)t)
Answer:
Nothing seems incorrect to me I feel u are doing great keep up the outstanding work.^-^
Hoped I Have Helped Honey Have A Nice Day "Peace"
Step-by-step explanation:
Answer:
x=−2
Step-by-step explanation:
1 Expand.
6-2x-12=3x+4
6−2x−12=3x+4
2 Simplify 6-2x-126−2x−12 to -2x-6−2x−6.
-2x-6=3x+4
−2x−6=3x+4
3 Add 2x2x to both sides.
-6=3x+4+2x
−6=3x+4+2x
4 Simplify 3x+4+2x3x+4+2x to 5x+45x+4.
-6=5x+4
−6=5x+4
5 Subtract 44 from both sides.
-6-4=5x
−6−4=5x
6 Simplify -6-4−6−4 to -10−10.
-10=5x
−10=5x
7 Divide both sides by 55.
-\frac{10}{5}=x
−
5
10
=x
8 Simplify \frac{10}{5}
5
10
to 22.
-2=x
−2=x
9 Switch sides.
x=-2
x=−2
(7, 3) is the answer I believe
Answer:
D
Step-by-step explanation:
To find the discriminant you do b^2-4(a)(c), which in this case gives you -28. If your discriminant is less than zero, you will have no real roots.
