Answer:
The function notation is given as:
$6 + $30 × x
f(x) = $6 + 30x
The dog walker charges $28.50
Step-by-step explanation:
Let the hourly rate be represented by x
A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30.
The function notation is given as:
$6 + $30 × x
F(x) = $6 + 30x
How much does the dog walker charge for a 45 minute walk?
We have to convert 45 minutes to 1 hour
60 minutes = 1 hour
45 minutes = x
x = 45/60
x = 3/4(hour)
Putting that in the function notation:
f(x) = $6 + 30x
x = 3/4
$6 + 30(3/4)
$6 + $22.5
= $28.50
Therefore, the dog walker charges $28.50
Answer:
C
Step-by-step explanation:
Short leg = x-6m
Longer leg =x
Hypotenuse = x+6m
x² + (x-6)² =(x+6)²
x² + x²-12x+36 = x²+12x+36
2x²-12x+36= x² +12x+36
2x²-12x+36-36= x² +12x+36-36
2x² - 12x-12x = x²+12x-12x
2x² -24x-x² = x²-x²
x² -24x = 0
x(x-24)=0
x = 24
Short leg = 24-6m = 18
Longer leg =24
Hypotenuse = 24+6m=30
Check
a² + b² = c²
18² +24² =30²
324 +576 = 900
900=900
General exponential equation
y = A(1+r)^x
where
A = initial value
r = rate increase (+) or decrease (-)
x = time period of the change
y = projected value
y = 300(1.05)^x
in this problem, x = years after 2017
we want to find an x that makes the value more than or equal to 650
650 <= 300(1.05)^x
