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ankoles [38]
3 years ago
6

The solublity rules for ionic compounds are shown in the textbook on page 330. However, as you know, you can't bring the textboo

k with you to exams. The solubility rules are also shown on the bottom of the Exam Information Sheet. Because this is a tool that you CAN access during excams, you need to practice using these solubility nules. Using the solubility rules on the Exam Information Sheet, predict whether the following compounds are soluble or insoluble in water. Use the drop-down menus provided. NIS | [ Select ] Mg3(POs)2 Select ) Li2CO3 ISelect ] NH4CI I Select ) 1 pts D Question 6 Which of the following best describes the solute in an aqueous solution of sucrose or C12H2201 (aq)? o c4t H' and o? ions C, H and O atoms C12H22011 molecules C atoms and H20 molecules
Chemistry
1 answer:
Alex Ar [27]3 years ago
7 0

Answer:

NiS insoluble

Mg₃(PO₄)₂ insoluble

Li₂CO₃ soluble

NH₄Cl soluble

C₁₂H₂₂O₁₁ molecules

Explanation:

<em>Predict whether the following compounds are soluble or insoluble in water.</em>

Based on the solubility rules we can say:

  • NiS: Sulfides of transition metals are highly insoluble.
  • Mg₃(PO₄)₂: All phosphates (except those with metals of Group 1) are insoluble so Mg₃(PO₄)₂ is insoluble.
  • Li₂CO₃: all salts of metals of Group 1 are soluble so Li₂CO₃ is soluble.
  • NH₄Cl: all salts of ammonium are soluble so NH₄Cl is soluble.

<em>Which of the following best describes the solute in an aqueous solution of sucrose or C₁₂H₂₂O₁₁(aq)?</em>

Sucrose is a molecular compound in which atoms are linked through covalent bonds. Thus, it does not ionize in water (is a non-electrolyte) and when it dissolves it exists as C₁₂H₂₂O₁₁ molecules.

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Can you show me the answer and explain?
Hitman42 [59]

Answer:

C

Explanation:

looking at a periodic table X is fluorine and Y is potassium

Fluorine is in group 7 and forms a 1- charge (which gains electrons) and potassium is in group 1 and forms a 1+ charge (which loses electrons)

Fluorine (X) has an electronic structure of 2,7 and needs to gain an electron from Potassium (Y) to have a full outer shell and potassium has an electronic structure of 2,8,8,1 so needs to lose an electron to have a full outer shell as well. This means that the electron that potassium (Y) has lost is given away to fluorine (X), so both elements become stable.

This is known as ionic bonding where metals (like potassium) lose electrons and non-metals (like fluorine) gain electrons to become more stable, forming ions

Any further clarification let me know

6 0
2 years ago
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Mkey [24]
Aye i can’t see the full question dawg, you gotta send a full picture of it
6 0
2 years ago
The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachlorid
stepladder [879]

Answer:

Final Answer: boiling point and high

Explanation:

3 0
3 years ago
Read 2 more answers
The elements silicon (atomic number 14) and chlorine (atomic number 17) are both in Period 3. Which is the more reactive element
Svetlanka [38]

Answer;

-Chlorine is more reactive than silicon

Explanation;

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5 0
3 years ago
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Nitrogen dioxide and water react to produce nitric acid, HNO3,
maw [93]

Answer:

Explanation:

a )

3NO₂(g) + H₂O(l) — -→ 2HNO₃(aq) + NO(g)

3 x 46 g       18 g            2 x 63 g       30 g

138 g of NO₂ requires 18 g of H₂O

28 g of NO₂ requires ( 18 / 138) x 28

= 3.65 g of H₂O.

b )

18 g of H₂O produces 30 g of NO gas

15.8 g of H₂O produces ( 30/18 ) x 15.8

= 26.33 g of NO gas .

c )

138 g of NO₂ produces 126 g of HNO₃

8.25 g  of NO₂ produces (126 / 138 ) x 8.25

= 7.53 g of HNO₃

7 0
3 years ago
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