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Lorico [155]
3 years ago
10

The freezing point of pure water is 0.0°C. How many grams of ethylene glycol (C2H6O2) must be mixed in 100.0 g of water to lower

the freezing point of the solution to -8.8°C? g
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

17.54 g

Explanation:

the freezing point of the solution to -8.8°C

depression in freezing point = 8.8°C

Molal freezing point depression constant of ethylene glycol  Kf = 3.11⁰C /m

ΔTf = Kf x m , m is no of moles of solute per kg of solvent .

Let gram of ethylene glycol required be x .

moles = m / mol weight of ethylene glycol

= x / 62

100 g of water = .1 kg

moles of solute dissolved in 1 kg of water

m = x / 62 x .1

m = 10 x / 62

Using the above equation for depression in freezing point

8.8 = 3.11 x 10 x / 62

x = 17.54 g .

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1 year ago
Need help !!!!! ASAP
gavmur [86]
<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

T_{2}=4K

<h2>Why?</h2>

We are given the volume, the first temperature and the new volume after the gas is compressed. To calculate the new temperature after the gas was compressed, we need to use Charles's Law.

Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

Now, to calculate the new temperature we need to assume that the pressure is kept constant, otherwise, the problem would not have a solution.

From Charle's Law, we have:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

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Then, isolating the new temperature and substituting the given information, we have:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

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Have a nice day!

7 0
4 years ago
A ground water tank has its height 2m. Calculate the pressure at its bottom when it is completely filled with water.​
Law Incorporation [45]

The pressure at the bottom : 19600 N/m²

<h3>Further explanation</h3>

Given

A ground water tank has its height 2m

Required

The pressure at its bottom

Solution

Hydrostatic pressure is the pressure caused by the weight of a liquid.  

The weight of a liquid is affected by the force of gravity.  

The hydrostatic pressure of a liquid can be formulated:  

\large{\boxed{\bold {P_h ~ = ~ \rho.g.h}}

Ph = hydrostatic pressure (N / m², Pa)  

ρ = density of liquid (kg / m³)  

g = acceleration due to gravity (m / s²)  

h = height / depth of liquid surface (m)  

ρ = density of water (kg / m³) = 1000

g = acceleration due to gravity = 9.8 m/ sec²

The pressure

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6 0
3 years ago
In a constant‑pressure calorimeter, 60.0 mL of 0.300 M Ba(OH)2 was added to 60.0 mL of 0.600 M HCl. The reaction caused the temp
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Answer:

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Explanation:

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ΔH = 57,042 j/mole H₂O = 57.04 Kj/mole H₂O

3 0
3 years ago
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