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Sergeeva-Olga [200]
3 years ago
14

How many atoms of N are in 137.0 grams of N2O3?

Chemistry
2 answers:
valina [46]3 years ago
6 0

Answer:

1.085 x 10²⁴

Explanation:

The answer is not in your choices, but it maybe due to a typo but to get the answer to this, you just need to convert the grams to moles, then moles to atoms.

First we get the mass of the molecule for every mole. Get the atomic mass of each element and multiply it by the number of atoms present then get their total.

N₂O₃

Element       number of atoms        Atomic mass       TOTAL

    N                          2                x          14.007            28.014

    O                          3                x          15.999           <u>47.997</u>

                                                                                      76.011 g/mole

So now we know for every 1 mole of N₂O₃ there are 76.011 g of N₂O₃.

Next we need to see how many moles of N₂O₃ are there in 137.0g of N₂O₃.

137.0g\times\dfrac{1mole}{76.011g}=1.802moles

Now we know that we have 1.802moles of N₂O₃.

We use Avogadro's constant to find out how many atoms there are. Avogadro's constant states that for every mole of any substance, there are 6.022140857 × 10²³ atoms.

1.802moles\times\dfrac{6.022140857\times10^{23}atoms}{1 mole}=1.085\times10^{24}atoms

quester [9]3 years ago
6 0

Answer: 2.17\times 10^{24}

Explanation:-

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

For N_2O_3

Mass  given = 137.0 g

Molar mass of  N_2O_3 = 76 g/mol

Putting values in above equation, we get:

\text{Moles of}N_2O_3 =\frac{137g}{76g/mol}=1.80mol

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles

1 mole of N_2O_3 contains =2\times 6.023\times 10^{23}=12.04\times 10^{23} atoms of nitrogen

1.80 moles of N_2O_3 contains =\frac{12.04\times 10^{23}}{1}\times 1.80=2.17\times 10^{24} atoms of nitrogen.

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Answer:

The answer to your question is: 101.2 g of CO2

Explanation:

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O₂ that reacted = 86.5 - 12.9 = 73.6 g

                     C     + O₂      ⇒        CO₂      The equation is balanced

                    27.6    73.6                 ?

MW               12        32                  44

Rule of three

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                  x = 27.6(44)/12 = 101.2 g of CO2

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                  x = 73.6(44)/32 = 101.2 g of CO2

6 0
3 years ago
Which interaction occurs when light goes into an object as heat energy?
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Absorbed light makes an object dark. Absorption of light is when the light is absorbed by the object and converts it into heat energy. The objects converts the wavelength of light into the larger wavelength of heat.  this makes the object warmer and produced energy. Absorption depends on the frequency of light that is transmitted. The wavelength of light defined as the distance between the the two successive troughs of the the light wave.

Therefore, Interaction occurs when light goes into an object as heat energy is Absorbed light.

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Answer : The amount of heat needed is, 1188 J

Explanation :

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c = specific heat capacity of copper = 0.40J/g^oC

T_1 = initial temperature = 20.0^oC

T_2 = final temperature = 74.0^oC

Now put all the given values in the above formula, we get:

q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC

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Hope this helps

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