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photoshop1234 [79]
3 years ago
8

What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 14.630 g to 3.000 g ?

Chemistry
1 answer:
nlexa [21]3 years ago
8 0

Answer:

Explanation:

The quantity of sugar in the bar of milky chocolate of  45 g is 25 g of sugar

u can use this information to calculate the amount of the sugar in any amount .

mass of sugar in 14.630 g →

     chocolate mass                 sugar mass

         45 g                                    25 g

       14.630                                     x      

                                                            X= mass of sugar = 8.13 g

now  for 3 gram of chocolate :

          45 g                                   25 g

           3.000                                 x

    X = 1.667 grams of sugar

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Solar energy converts ___ into either ___ energy or electrical energy.
IceJOKER [234]

Answer:

Hey mate....

Explanation:

This is ur answer.....

<h2>Solar radiation can be converted either into thermal energy (heat) or into electrical energy.</h2>

Hope it helps!

mark me brainliest plz......

Follow me! :)

4 0
2 years ago
Read 2 more answers
Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.
qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m= 32 g
  • ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 \frac{J}{g*C} *14 °C

Solving:

Q= 1,874.432 J

<u><em>The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J</em></u>

7 0
2 years ago
A fish may have hundreds of offspring at a time and only a small number can survive. which characteristics of fish might allow t
mafiozo [28]
Well depends on what type of fish the parent is but i guess you can say:
what they eat
teeth
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blending in,etc
8 0
3 years ago
Alkenes can be converted to alcohols by reaction with mercuric acetate to form a ?-hydroxyalkylmercury(II) acetate compound, a r
Goshia [24]

Answer:

The simplified mechanism and products are on the picture.

Explanation:

If we have the symmetrical alkene the addition of mercury and OH group is not regioselective but when we have more donors for one of Carbons in alkene then the OH group will go there.

3 0
3 years ago
Read 2 more answers
What volume did a helium-filled balloon have at 22.5 c and 1.95 atm if it’s new volume was 56.4 mL at 3.69 atm and 11.9c
Veseljchak [2.6K]

This is an exercise in the general or combined gas law.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • T₁ = 22.5 °C + 273 = 295.5 K
  • P₁ = 1.95 atm
  • V₁ = ¿?
  • P₂ = 3.69 atm
  • T₂ = 11.9 °C + 273 =  284.9 k
  • V₂= 56.4 ml

We use the following formula:

P₁V₁T₂ = P₂V₂T₁ ⇒ General formula

Where

  • P₁ = Initial pressure
  • V₁ = Initial volume
  • T₂ = Initial temperature
  • P₂ = Final pressure
  • V₂ = final volume
  • T₁ = Initial temperature

We clear the formula for the initial volume:

\boldsymbol{\sf{V_{1}=\dfrac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}  } }

We substitute our data into the formula to solve:

\boldsymbol{\sf{V_{1}=\dfrac{(3.69 \not{atm})(56.4 \ ml)(295.5 \not{k})}{(1.95 \not{atm})(284.9\not{k})}  }}

\boldsymbol{\sf{V_{1}=\dfrac{61498.278}{555.555} \ lm }}

\boxed{\boldsymbol{\sf{V_{1}=110.697 \ lm }}}

The helium-filled balloon has a volume of <u>110.697 ml.</u>

6 0
1 year ago
Read 2 more answers
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