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3 years ago

This is Math 3. I am confused because of the -2

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

Answer:

x=5

Step-by-step explanation:

for the work I use a website called symbolab.com and it does all the work and everything for you!

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Given: 5n - 42 = 12n; Prove: n= -6 What are the Statements What are the Reasons

asambeis [7]

Answer:

-72=-72

Step-by-step explanation:

5n-42=12n

n=-6

5*(-6)-42 = 12*(-6)

-30-42=-72

-72=-72

So, n= -6 is the right number for this equation

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3 years ago

The length between (3, 8) and (-2, -4) is ______?

True [87]

Answer:

Step-by-step explanation:

to find the length between two point you've got to use the formula

√(x2-x1)^2 +(y2-y1)^2

√(-2-3)^2 + (-4-8)^2

√(-5)^2 + (-12)^2

√ 25+144

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3 years ago

Limit definition for slope of the graph, equation of tangent line point for f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

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