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julia-pushkina [17]
3 years ago
8

Common static electricity involves charges ranging from nanocoulombs to microcoulombs. How many electrons are needed to form a c

harge of -2.00 nC?
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

To solve this problem we will use the ratio given by the amount of total charge (q) equivalent to the individual charge of each electron (e) multiplied by the total number of electrons (n) present, that is,

q = ne

Here

q = Total charge

e = Electron charge

Our value of the charge is

q = -2nC= -2*10^{-9}C

We know that the charge in a electron is

e = -1.6*10^{-19}C

Replacing we have then

(-2*10^{-9}) = n(-1.6*10^{-19})

n = \frac{-2*10^{-9}}{-1.6*10^{-19}}

n = 1.25*10^{10} electrons

Therefore the number of electrons needed to form a charge of -2nC is 1.25*10^{10} electrons

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I have explained in the paper.

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While driving a 2150 kg car, carl steps on the gas pedal, accelerating at 4.0 m/s2. If the coefficient of friction between his c
Mrac [35]

Answer:

d. 3332.5 [N]

Explanation:

To solve this problem we will use newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.

Here we have two forces, the force that pushes the car to move forward and the friction force.

The friction force is equal to the product of the normal force by the coefficient of friction.

f = N * μ

f = (m*g) * μ

where:

N = weight of the car = 2150*9.81 = 21091.5 [N]

μ = 0.25

f = (21091.5) * 0.25

f = 5273 [N]

Now as the car is moving forward, the car wheels move clockwise. The friction force between the wheels of the car and the pavement must be counterclockwise, i.e. counterclockwise. Therefore the direction of this force is forward. This way we have:

F + f = m*a

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6 0
3 years ago
The chart show the masses and velocities of two colliding objects that stick together after a collision.
finlep [7]

Answer:

<u><em></em></u>

  • <u><em>1,500 kg.m/s</em></u>

Explanation:

First, arrange the information in a table:

Object        Mass (kg)           Velocity (m/s)

  A                    200                      15

  B                     150                    - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

<u>Momentum before the collision, P₁</u>:

          P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}

         P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\  P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s

<u>Momentum after the collision</u>:

  • As stated, it es equal to the momentum before the collision: 1,500 kg . m/s
6 0
4 years ago
Please help on this one
Airida [17]

The answer for this would be "B".

6 0
3 years ago
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