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2 years ago

7

Hello, I want to ask. . anyone knows the answer.

1 answer:

sasho [114]2 years ago

5 0

Answer:

C?

Explanation:

Please give brainliest.

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At 6: 00 am, a motorbike set off from town A to town B at a speed of 40km/h. At the same time, a car set off from town B to town

Keith_Richards [23]

Answer:

One would need to know how far apart the towns are:

T = SA / 40 time it takes for first cyclist to travel S1

T = SB / 60 time it takes for cyclist B to travel distance S2

SA + SB = S the distance between the towns

SB = 60 / 40 SA = 1.5 SA

SA + 1.5 SA = S

S = 2.5 SA where cyclist travels distance SA

The time will depend on the separation of the towns.

4 0

1 year ago

The force of Earth's gravity on a capsule in space will lessen as it moves farther away. If the capsule moves to twice its dista

Bess [88]

Answer: One quarter of the force

Explanation:

According to Newton's law of Gravitation, the force $F$ exerted between two bodies of masses $m1$ and $m2$ and separated by a distance $r$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$ (1)

Where $G$ is the gravitational constant

This means that the gravity force decreases when the distance between these two bodies increases.

In this context, if the distance between the capsule and the Earth increases twice, the new distance will be $2r$ .

Substituting this distance in (1):

$F=G\frac{(m1)(m2)}{(2r)^2}$ (2)

$F=G\frac{(m1)(m2)}{4r^2}$

<u>Finally:</u>

$F=\frac{1}{4}G\frac{(m1)(m2)}{r^2}$ >>>This means the force toward Earth becomes one quarter "weaker"

3 0

2 years ago

A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same directionWith the given uncertainties, what is

Anika [276]

Answer:

The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.

Explanation:

For 2 quantities A and B represented as

$A\pm \Delta A$ and $B\pm \Delta B$

The sum is represented as

$Sum=(A+B)\pm (\Delta A+\Delta B)$

For the the values given to us the sum is calculated as

$Sum=(2.9+3.9)\pm (0.1+0.2)$

$Sum=6.8\pm 0.3$

Now the since the uncertainity inthe sum is $\pm 0.3$

The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity

Thus closest distance equals $6.8-0.3=6.5$ meters

3 0

3 years ago

A car is traveling south at a speed of 54 miles per hour and then begins traveling at a speed of 55 miles per hour but continues

Kazeer [188]

Explanation:

VELOCITY: BECAUSE ITS A VECTOR QUANTITY

7 0

2 years ago

Identify the kinds of notes and rest found in the following musical lines.

Snowcat [4.5K]

Answer: Thats all I know about notes and rests, srry if this not what ur expecting.

Explanation:

8 0

2 years ago