The momentum of the second ball was 15 kg.m/s.
<h3>What is inelastic collision?</h3>
In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.
In the given question,
Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.
Initial velocity of 1st ball of mass 3 kg is 1 m/s.
So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.
According to Principle of conservation of linear momentum for this inelastic collision,
Initial momentum of first ball + initial momentum of second ball = final momentum of the system
⇒ initial momentum of second ball = final momentum of the system - Initial momentum of first ball
= 18 kg.m/s - 3 kg.m/s.
= 15 kg.m/s.
Hence, initial momentum of second ball = 15 kg.m/s.
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Pints and ounces are both very small while gallons are very large so I would say about a Quart.
A set of data has a mean of 12 and a standard deviation of 3. A data point of the set has a z-score of 1.3. What does a z-score of 1.3 mean?
The data point is 1.3 standard deviations away from 3
The data point is 1.3 standard deviations away from 12.
The data point is 3 standard deviations away from 1.3.
The data point is 3 standard deviations away from 12.
its B
When the forward and reverse paths of a change occur at the same rate, "<span>B. the system is in equilibrium". This is because there is no net flow of reactants at this time. This stage can be reached quickly or after long periods of time.</span>
