Answer:
7.66×10⁻⁵ K⁻¹
Explanation:
From the question,
γ = (v₂-v₁)/[v₁(t₂-t₁)]....................... Equation 1
Where γ = coefficient of volume expansion, v₁ = initial volume, v₂ = Final volume, t₁ = initial temperature, t₂ = Final Temperature.
Given: v₁ = 26.1 cm³, v₂ = 26.2 cm³, t₁ = 25 °C, t₂ = 75 °C.
Substitute these values into equation 1
γ = (26.2-26.1)/[26.1(75-25)]
γ = 0.1/(26.1×50)
γ = 0.1/1305
γ = 7.66×10⁻⁵ K⁻¹
Hence the coefficient of volume expansion is 7.66×10⁻⁵ K⁻¹
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
Answer:
D. Vectors are quantities described by both magnitude and direction.
Explanation
Answer:
B. q = 2.5 x 10^-1 C
Explanation:
Formula: E = F/q
Given information:
E = 40 N/C
F = 10N
--> q = F/E = 10/40 = 0.25 C
or q = 2.5 x 10^-1 C
Explanation:
If the distance between the bottom of the ladder and the wall is x, then:
cos θ = x / 10
Taking derivative with respect to time:
-sin θ dθ/dt = 1/10 dx/dt
Substituting for θ:
-sin (acos(x / 10)) dθ/dt = 1/10 dx/dt
Given that x = 6 and dx/dt = 1.1:
-sin (acos(6/10)) dθ/dt = 1/10 (1.1)
-0.8 dθ/dt = 0.11
dθ/dt = -0.1375
The angle is decreasing at 0.1375 rad/s.